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kodGreya [7K]
2 years ago
14

I need the answer to the below question

Mathematics
1 answer:
kiruha [24]2 years ago
3 0
Send your snap I can help
You might be interested in
1. Prove or give a counterexample for the following statements: a) If ff: AA → BB is an injective function and bb ∈ BB, then |ff
Fantom [35]

Answer:

a) False. A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1

b) True

c) True

d) B = {1}, A = N, f: N ⇒ {1}, f(x) = 1

Step-by-step explanation:

a) lets use A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1. Here f is injective but 2 is an element of b and |f−¹({b})| = 0., not 1. This statement is False.

b) This is True. If  A were finite, then it can only be bijective with another finite set with equal cardinal, therefore, B should be finite (and with equal cardinal). If A were not finite but countable, then there should exist a bijection g: N ⇒ A, where N is the set of natural numbers. Note that f o g : N ⇒ B is a bijection because it is composition of bijections. This, B should be countable. This statement is True.

c) This is true, if f were surjective, then for every element of B there should exist an element a in A such that f(a) = b. This means that  f−¹({b}) has positive cardinal for each element b from B. since f⁻¹(b) ∩ f⁻¹(b') = ∅ for different elements b and b' (because an element of A cant return two different values with f). Therefore, each element of B can be assigned to a subset of A (f⁻¹(b)), with cardinal at least 1, this means that |B| ≤ |A|, and as a consequence, B is finite.

b) This is false, B = {1} is finite, A = N is infinite, however if f: N ⇒ {1}, f(x) = 1 for any natural number x, then f is surjective despite A not being finite.

4 0
3 years ago
Please help me with this please 2
kondaur [170]
Put this into a scientific calculator
1/3 x pi x 18 squared x 16
8 0
3 years ago
Theo used to drive 60 miles to work each day. His new home is now 20 miles away
posledela

Answer:

66.6% decrease in distance

Rounded 67%

He is traveling 1/3 of what he used to travel

Step-by-step explanation:

8 0
2 years ago
can you solve the question but tell me how to do it I'm trying to study but don't know how to solve it?
Vedmedyk [2.9K]

Answer:

8x+19=9x+9

Step-by-step explanation:

Simplifying

(8x + 19) = (9x + 9)

Reorder the terms:

(19 + 8x) = (9x + 9)

Remove parenthesis around (19 + 8x)

19 + 8x = (9x + 9)

Reorder the terms:

19 + 8x = (9 + 9x)

Remove parenthesis around (9 + 9x)

19 + 8x = 9 + 9x

Solving

19 + 8x = 9 + 9x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9x' to each side of the equation.

19 + 8x + -9x = 9 + 9x + -9x

Combine like terms: 8x + -9x = -1x

19 + -1x = 9 + 9x + -9x

Combine like terms: 9x + -9x = 0

19 + -1x = 9 + 0

19 + -1x = 9

Add '-19' to each side of the equation.

19 + -19 + -1x = 9 + -19

Combine like terms: 19 + -19 = 0

0 + -1x = 9 + -19

-1x = 9 + -19

Combine like terms: 9 + -19 = -10

-1x = -10

Divide each side by '-1'.

x = 10

Simplifying

x = 10

6 0
1 year ago
Read 2 more answers
1. Evaluate: 5 ÷1 + 3 + 7​
Elena-2011 [213]

Answer:

15

Step-by-step explanation:

5÷1+3+7

PEMDAS

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

5÷1= 5, then 5+3=8, then 8+7= 15

3 0
3 years ago
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