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nydimaria [60]
3 years ago
6

How many of the first 100 positive integers are divisible by 2, 3, or 5?.

Mathematics
1 answer:
attashe74 [19]3 years ago
3 0

Answer:

74

Step-by-step explanation:

50+33+20−16−6−10+3=74

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Step-by-step explanation:

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Question 26 pleaseee
LuckyWell [14K]

Answer:

The inequality is 55+10x\leq 105

The greatest length of time Jeremy can rent the jet ski is 5 and Jeremy can rent maximum of 135 minutes.

Step-by-step explanation:

Given: Cost of first hour rent of jet ski is $55

          Cost of each additional 15 minutes of jet ski is $10

          Jeremy can spend no more than $105

Assuming the number of additional 15-minutes increment be "x"

Jeremy´s total spending would be first hour rental fees and additional charges for each 15-minutes of jet ski.

Lets put up an expression for total spending of Jeremy.

\$55+ \$ 10\times x

We also know that Jeremy can not spend more than $105

∴ Putting up the total spending of Jeremy in an inequality.

\$ 55+\$10x\leq \$ 105

Now solving the inequality to find the greatest number of time Jeremy can rent the jet ski,

⇒ \$ 55+\$10x\leq \$105

Subtracting both side by 55

⇒ \$ 10x\leq \$50

Dividing both side by 10

⇒x\leq \frac{50}{10}

∴ x\leq 5

Therefore, Jeremy can rent for 60\ minutes + 5\times 15\\= 60\ minutes + 75= 135\ minutes

Jeremy can rent maximum of 135 minutes.

5 0
3 years ago
Is 7 1/8 grater or less than 7.025
aliina [53]
7 1/8 is greater than 7.025 because if you convert it into a decimal (8 * 7 = 56 + 1 = 57/8 =....) you get 7.125, which is obviously bigger (1>0)
3 0
3 years ago
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The elements that compose seawater, along with the corresponding percents, are shownin the table.Mrs. Buller collects a 500-ml s
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Answer: Mrs.Buller collects a 500-ml sample of seawater for her chemistry class, and it has 1.94% of chlorine, we have to determine the amount of chlorine in the sample:

\begin{gathered} C=\frac{1.94}{100}\times500=9.7ml \\ C=9.7ml \end{gathered}

Therefore the chlorine content in 500ml of water is 9.7ml.

3 0
1 year ago
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