Answer:
Second option - The bond is very polar
Explanation:
Electronegativity of an basically refers to the degree at which an electron is able to attract electrons to itself.
There are different types of bonds between atoms, depending on the electronegativity of the atoms.
When there is a large difference in electronegativity, it pretty much means that one atom would draw electrons more than the other. When this happens, the bond is said to be polar because there is uneven distribution of the charges.
The second option is the correct answer in thus question.
Hello!
To solve this problem we are going to use the
Henderson-Hasselbach equation and clear for the molar ratio. Keep in mind that we need the value for Acetic Acid's pKa, which can be found in tables and is
4,76:
![pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )](https://tex.z-dn.net/?f=pH%3DpKa%20%2B%20log%20%28%20%5Cfrac%7B%5BCH_3COONa%5D%7D%7B%5BCH_3COOH%5D%7D%20%29%20)
![\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BCH_3COOH%5D%7D%7B%5BCH_3COONa%7D%3D%2010%5E%7B%28pH-pKa%29%5E%7B-1%7D%7D%3D10%5E%7B%284-4%2C76%29%5E%7B-1%7D%7D%3D5%2C75%20)
So, the mole ratio of CH₃COOH to CH₃COONa is
5,75Have a nice day!
Answer:
168.56 mL
Explanation:
density = mass/volume, use basic algebra skills to replace the volume and solve
Answer:
ver explicacion
Explanation:
Zn (s) + 2HCl (ac) ---> ZnCl2 (ac) + H2 (g)
El zinc se oxida y el hidrógeno se reduce. HCl es el agente oxidante mientras que Zn es el agente reductor.
2Na (s) + H2SO4 (ac) ----> Na2SO4 (ac) + H2 (g)
El Na se oxida y el hidrógeno se reduce. El ácido sulfúrico es el agente oxidante, mientras que el sodio metálico es el agente reductor de tge.
Ca (OH) 2 (ac) + H2CO3 (ac) ------> CaCO3 (s) + 2H2O (l)
Esta no es una reacción redox ya que no hay cambios en el número de oxidación de izquierda a derecha.
