Answer:
8 moles = 16 gm of H2 left over
Explanation:
The balanced equation is
2 H2 + O2 ===> 2 H2 O
20 g H2 = 20 g / 2 gm/mole = 10 moles of H2
32 g O2 = 32g / 32 g / mole = 1 mole O2
From the balanced equation, you can see each 2 moles of H2 requires 1 Mole of O2
you would need 20 moles of O 2 to react withe the 10 moles of H2
but you only have 1 mole of O2 so 8 moles of H2 will be left
<h2>a)
The rate at which 
is formed is 0.066 M/s</h2><h2>b)
The rate at which molecular oxygen 
is reacting is 0.033 M/s</h2>
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate in terms of disappearance of 
= ![-\frac{1d[NO]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BNO%5D%7D%7B2dt%7D)
= 0.066 M/s
Rate in terms of disappearance of = ![-\frac{1d[O_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BO_2%5D%7D%7Bdt%7D)
Rate in terms of appearance of = ![\frac{1d[NO_2]}{2dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BNO_2%5D%7D%7B2dt%7D)
1. The rate of formation of
![-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BNO_2%5D%7D%7B2dt%7D%3D%5Cfrac%7B1d%5BNO%5D%7D%7B2dt%7D)
![\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BNO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B2%7D%7B2%7D%5Ctimes%200.066M%2Fs%3D0.066M%2Fs)
2. The rate of disappearance of
![-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7Bd%5BNO%5D%7D%7B2dt%7D)
![-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.066M%2Fs%3D0.033M%2Fs)
Learn more about rate law
brainly.com/question/13019661
https://brainly.in/question/1297322
The ideal gas under STP is 22.4 L/mol. While the gas has a rule of P1V1/T1=P2V2/T2. So the volume under 101 kPa and 273 K is 0.2*22.4=4.48 L.
Answer:
0.05 mol
Explanation:
Moles = Mass / Mr (Relative formula mass)
Ar of aluminium = 27
Ar of sulphur = 32
Ar of oxygen = 16
Mr of Al2(S2O3)2 = (27×2)+((32×2)×3)+((16×3)×3)= 390
Moles = 18.5g / 390
Moles = 0.05 mol
The first trna's anticodon loop, which will complement this mrna, is 3' GGC 5'.
<h3>What is anticodon ?</h3>
A complementary codon in messenger RNA binds to a triplet of nucleotide bases in transfer RNA that identifies the amino acid delivered during protein synthesis at a ribosome.
A codon is a trio of nucleotides, or triplet, that can be found on mRNA and codes for a certain amino acid when it is translated. A bond is created when an anticodon, which is a three-nucleotide sequence on tRNA, meets with the matching sequence on mRNA.
Each tRNA has a trio of bases known as an anti-codon. to determine the entire anti-codon sequence required to match a certain strand of mRNA. to match the complementary nucleotides in the mRNA sequence.
To learn more about anticodon from the given link:
brainly.com/question/14917337
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