Question

Read the given equation.

Answer 1

Answer: b. 12.9 grams

Explanation:

$2Na+2H_2O\rightarrow 2NaOH+H_2$

According to avogadro's law, 1 mole of every gas occupies 22.4 Liters at STP ,contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to the molecular mass.

Thus at STP :

1 mole of hydrogen is produced by 2 moles of sodium metal

i.e. 22.4 L of $H_2$ is produced by 46 gram of sodium metal

6.3 L of $H_2$ is produced by=$\frac{46}{22.4}\times 6.3=12.9gram$ of sodium metal

Answer 2

A that would be the correct answer