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JulsSmile [24]
2 years ago
14

What is 5+5x62 divided by 2

Mathematics
2 answers:
Brut [27]2 years ago
4 0

Answer:

160

Step-by-step explanation:

5+5x62 divided by 2

5+(5x62) divided by 2

5+310 divided by 2

5+ 155=

160

aliina [53]2 years ago
3 0

Answer:

the answer is 310

Step-by-step explanation: 5+5 = 10 and 10 x62= 620

620 divided by 2 = 310

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Indigo Depot is having a clearance sale of their fall items. A jacket that originally cost $120 before any discount is on sale f
Sauron [17]

Answer:

The final price is $66.

Step-by-step explanation:

This question can be solved by a rule of three.

The initial price was of $120.

Initially, there was a discount of 15%. Then, there is another discount on the initial price. So the total discount is of 15+30 = 45%.

So the final price will be 100-45 = 55% = 0.55 of the initial price.

So

$120 - 1

x - 0.55

x = 0.55*120 = 66

The final price is $66.

5 0
3 years ago
There are 25 nickels and quarters. W coins are nickels and the rest are quarters. Write and algebraic expression for the number
den301095 [7]
The algebraic expression would be that Quarters = 25 - W
5 0
3 years ago
Can someone help me for this question please? I just keep getting wrong answer! Pls someone explain to me step by step! ASAP!!!
Kobotan [32]

Answer:

  84 feet

Step-by-step explanation:

This problem involves several steps. The first step is to realize that the given figure does not show the required number of vertical stringers. It shows 5, but there will be 7 of them. The given diagram is helpful in that it shows a vertical stringer on the centerline of the arches.

The second step is to write a function that will tell you how long the stringer will be. I find it convenient to write the equation for an arch shape such as this using the parent function h(x) = 1-x^2. This parent function gives an arch of height 1 and width 1 from center (a total width of 2). You want an arch that is 16 ft high and 40 ft wide (one side from center), so you must scale this parent function both horizontally (by 40) and vertically (by 16). It becomes ...

  H(x) = 16(1 -(x/40)^2)

The taller arch is twice this height, so the length of a vertical stringer at position x is

  vertical length = 2H(x) -H(x) = H(x)

That is, the function H(x) we defined can be used to find the length of the stringers.

The third step is to find the stringer lengths. It can save some energy if you realize that the problem is symmetrical, so that the stringer at x=-30 is the same length as the one at x=30. We need to find stringer lengths every 10 feet from -40 feet to +40 feet. Of course, the ones at ±40 feet are zero length, because that is where the two arches meet.

  H(-30) = 16(1 -(3/4)^2) = 7

  H(-20) = 16(1 -(1/2)^2) = 12

  H(-10) = 16(1 -(1/4)^2) = 15

  H(0) = 16

Then the fourth step is to add up the stringer lengths, rounding the result as required.

  7 +12 +15 +16 +15 +12 +7 = 16 + 2(34) = 84 . . . . feet (no rounding needed)

Finally, you need to answer the question asked:

  The sum of vertical stringer lengths is 84 feet.

5 0
3 years ago
Solve for x in the equation x2 - 4x-9 = 29.
erastova [34]

Answer:

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

Step-by-step explanation:

One is given the following equation;

x^2-4x-9=29

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

x^2-4x-9=29

x^2-4x-38=0

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

ax^2+bx+c

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Substitute the coefficients of the given equation in and solve for the roots;

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}

Simplify,

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}

Therefore, the following statement can be made;

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

8 0
2 years ago
A=20 find the volume round to the nearest 10th
lianna [129]
Are you sure there weren't any other numbers in the problem? You can't solve for the volume with out at least two numbers for length, width, or height. Or are you solving for a cube?

8 0
3 years ago
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