The sixth term of an arithmetic sequence is 6
<h3>How to find arithmetic sequence?</h3>
The sum of the first four terms of an arithmetic sequence is 10.
The fifth term is 5.
Therefore,
sum of term = n / 2(2a + (n - 1)d)
where
- a = first term
- d = common difference
- n = number of terms
Therefore,
n = 4
10 = 4 / 2 (2a + 3d)
10 = 2(2a + 3d)
10 = 4a + 6d
4a + 6d = 10
a + 4d = 5
4a + 6d = 10
4a + 16d = 20
10d = 10
d = 1
a + 4(1) = 5
a = 1
Therefore,
6th term = a + 5d
6th term = 1 + 5(1)
6th term = 6
learn more on sequence here: brainly.com/question/24128922
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Let the number be a ....
=>Number doubled : 2a ..
=>Eight less than the no. Doubled : 2a - 8
=>Eight less than the no. doubled is 20 more than the no. : 2a - 8 = 20 + a
=>2a - 8 - 20 - a = 0
=>2a -a - 20 -8 = 0
=>a -28 = 0
=>a = 28
=>so the number is 28...
Hope it helps!!!
Draw a graph with those points. then draw a vertical line through the graph. if the line passes through twice then it’s not a function if it only passes through once it’s a function.
