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Oxana [17]
3 years ago
12

An acute angle’s measure is:

Mathematics
2 answers:
Tpy6a [65]3 years ago
6 0
An acute angles measure is 90°
3241004551 [841]3 years ago
3 0

Answer:

>90°

degrees from below 90 degrees

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Solve the system using any method.<br> 6x+2y =7<br> y= 2-3x
Drupady [299]

Answer:

there is no solution

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3 years ago
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Answer this question ​
lutik1710 [3]

Answer:

Step-by-step explanation:

1. Eggs are sold at a price of P 105.00 per dozen.

Rate = \frac{1}{105}

2. The carpentry job can be done by 3 carpenters in 4 days.

Rate at which each carpenter works = \frac{4}{3} = 1\frac{1}{3} days

This shows that each carpenter worked for an average of 1.3333 days to complete the job.

3. Five tickets are sold at P 600.00

The price for one ticket = \frac{600}{5}

                                       = 120

One ticket is sold for P 120.00.

4. The dollar's rate is P 52.00.

This implies that;

1 dollar = P 52.00

dollar rate = \frac{1}{52}

5. The ratio of water to milk in the recipe is 1 to 4.

This implies that to 1 measure of water, 4 measures of milk is used in the recipe.

rate = \frac{1}{4}

5 0
3 years ago
Describe the main parts of a proof.​
Vsevolod [243]

Answer:

Is there a picture?

Step-by-step explanation:

7 0
4 years ago
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Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

5 0
3 years ago
The data show the ages of 13 people attending a dinner party. 37, 42, 44, 46, 47, 49, 51, 53, 54, 55, 57, 61, 63 a. Find the min
NemiM [27]

Answer: Median: 50, Minimum Value: 37, Maxium Value: 63, First Quartile: 44, Third Quartile: 57  

Step-by-step explanation:

To find the median we have to line up the number from least to greatest. Since the number is even we have two numbers.

(37, 42, 44, 46, 47, )(49, 51,)(54, 55, 57, 61, 63)

            |                          |                        |

  1st  Quartile        2nd Quartile     3rd Quratile

49 + 51 = 100 ÷ 2 = 50

Median = 50

The minimum value is the least number, therefore 37

The maxium number is the greatest number, therefore 63

The first quartile is the middle number in the first quartile, therefore 44

The third quartile is the middle number in the third quartile, therefore 57

I hope this helps!

6 0
3 years ago
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