Answer:
log(x^7·y^2)
Step-by-step explanation:
The applicable rules are ...
... log(a^b) = b·log(a)
... log(ab) = log(a) +log(b)
_____
The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.
The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.
Now, you have the sum ...
... log(x^7) +log(y^2)
The second rule tells you this can be rewritten as ...
... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection
Answer:
it c
Step-by-step explanation:
Initial velocity (u) = 0m/s
Final velocity (v) = 20m/s
Time (t) = 10 s
Acceleration (a)
= (v - u)/t
= [(20m/s) - (0m/s)]/10s
= (20m/s)/10s
= (20m/s²)/10
=> 2m/s²
Answer:
A
Step-by-step explanation:
Answer:
z=-21
Step-by-step explanation: (9-3)/2=(6+z)/5
We move all terms to the left:
(9-3)/2-((6+z)/5)=0
We add all the numbers together, and all the variables
-((z+6)/5)+6/2=0
We add all the numbers together, and all the variables
-((z+6)/5)+3=0
We multiply all the terms by the denominator
-((z+6)+3*5)=0
We calculate terms in parentheses: -((z+6)+3*5), so:
(z+6)+3*5
We add all the numbers together, and all the variables
(z+6)+15
We get rid of parentheses
z+6+15
We add all the numbers together, and all the variables
z+21
Back to the equation:
-(z+21)
We get rid of parentheses
-z-21=0
We add all the numbers together, and all the variables
-1z-21=0
We move all terms containing z to the left, all other terms to the right
-z=21
z=21/-1
z=-21