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olga2289 [7]
2 years ago
13

Help me with this pls​

Mathematics
1 answer:
Anton [14]2 years ago
5 0

\tt 4:2\dfrac{2}{3}=x:4\\\\4:\dfrac{8}{3}=x:4\\\\x=16:\dfrac{8}{3}=6

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What is an
miv72 [106K]

Answer:

y=1/4x + 1

Step-by-step explanation:

first equation,,y=1/4x - 1

G1 = G2

G2 = 1/4

y+1 /x+8 =1/4

4y = X + 8 -4

4y =x + 4

y = 1/4x + 1

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An online flower service sells boxes of roses. Each box contains one dozen roses of only one color. The choices are red, white,
Akimi4 [234]

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The answer is 21

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The answer to this is negative
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3 years ago
Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

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\bar {x}_2 = 12

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σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

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3 years ago
Expand. 4(5x + 3) 4(5x + 3)
Effectus [21]
400x to the power of 2 + 480x + 144
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2 years ago
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