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Naily [24]
3 years ago
5

What is 1+17+13+23+35+12+12+35+34

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0
The answer is 182, i hope this helps!

please mark as brainliest <3
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Use the power rule &amp; the power of a product rule to simplify the expression. (2p^4)^6
Papessa [141]
(2p^4)^6 = (2^6)p^(4 x 6) = 64p^24
6 0
4 years ago
A football player runs 13 1/2 yards how many feet does he run?
elixir [45]

Answer:

40 and a half feet

Step-by-step explanation:

1 meter=3 feet

13.5m=40.5f

3 0
3 years ago
An electronics hobbyist has three electronic parts cabinets with two drawers each.
Andrews [41]

Answer:

a) 0.5 = 50% probability that an NPN transistor will be selected.

b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types

c) 66.67% probability that it comes from the cabinet that contains only NPN transistors

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

a) What is the probability that an NPN transistor will be selected?

1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.

So

p = \frac{1}{3}*1 + \frac{1}{3}*0 + \frac{1}{3}*0.5 = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = 0.5

0.5 = 50% probability that an NPN transistor will be selected.

b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?

Here we use the conditional probability formula.

Event A: NPN transistor

Event B: From the third cabinet.

50% probability that an NPN transistor will be selected, so P(A) = 0.5.

1/6 probability that it is from the third cabinet and NPN, so P(A \cap B) = \frac{1}{6}

The desired probability is:

P(B|A) = \frac{\frac{1}{6}}{0.5} = 0.3333

0.3333 = 33.33% probability that it came from the cabinet that contains both types.

c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?

Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So

x + 33.33 = 100

x = 66.67

66.67% probability that it comes from the cabinet that contains only NPN transistors

6 0
3 years ago
Money in a particular savings account increases by 6% after a year. How much money will be in the account after one year if the
Alona [7]

Answer:

Step-by-step explanation:

34,999999

5 0
3 years ago
All sides of quadrilateral ABCD are tangent to circle P.
VARVARA [1.3K]

Answer:

44.4 units

Step-by-step explanation:

Recall: 2 tangents drawn from an external point from a circle are congruent

Perimeter of the quadrilateral = AB + BC + CD + AD

AB = 3.1 + 8 = 11.1

BC = 3.1 + 8 = 11.1

CD = 11.1 (given)

AD = 8 + 3.1 = 11.1

Perimeter = 11.1 + 11.1 + 11.1 + 11.1

= 44.4 units

6 0
3 years ago
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