Cos(<span>θ) < 0, so we know it would be in Quadrant 2 or 3
then csc(</span>θ) = 257, but csc(θ) = 

 = 257
==> sin(<span>θ) = 

it is positive, so now we can determine that is in Quadrant 2
sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj: 

cosθ = 

tanθ = 

cos<span>θ = </span>
 
 
        
        
        
Answer:
Below.
Step-by-step explanation:
Part A: 
Part B: Degree = 2, Classification = Quadratic
Part C: The polynomial is closed because it is multiplied. You CANNOT close under division.
 
        
             
        
        
        
Answer:
2134
Step-by-step explanation:
 
        
                    
             
        
        
        
Closest would be 8 43/200
        
             
        
        
        
The slope intercept form of a line is y = mx + b
Plug in the slope, 6, into m.
Rewrite the equation;
- y = 6x + b
- We need to find b, your y-intercept, to finish this equation.
Plug in your point coordinate, (x, y) ⇒ (-12, -14) into the equation.
Solve for b to find the y-intercept.
Your new equation (your answer) is<em> </em>y = 6x + 58.