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vodka [1.7K]
1 year ago
10

I believe you need to use the quadratic formula for this one, but I am not sure!

Mathematics
1 answer:
Nataly [62]1 year ago
6 0
4x^2+13=49

To solve the value of x in the above equation, here are the steps.

1. Subtract 13 on both sides of the equation.

\begin{gathered} 4x^2+13-13=49-13 \\ 4x^2=36 \end{gathered}

2. Divide both sides of the equation by 4.

\begin{gathered} \frac{4x^2}{4}=\frac{36}{4} \\ x^2=9 \end{gathered}

3. Get the square root on both sides of the equation.

\begin{gathered} \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}

The possible values of x are +3 and -3. The smaller value is -3.

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If A, B, and Care 2x2 matrices; and det(A) = -2, det(B) = -3, and det(C)=-4 then compute: det(4C^TA^-1 C^TB^3) = 0 Official Time
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3/5 of a certain class left on a field trip. 1/3 of the students who stayed behind did not want to go on the field trip (all the
Tom [10]

Answer:

11/15

Step-by-step explanation:

In this kind of problem, it is cool to always have a value for the total number of students. We can choose any arbitrary value for this. So let’s say the total number of students is 120.

Now we were told 3/5 left for the field trip. The number that left corresponds to 3/5 of 120 = 72 students. The number that didn’t go on the field trip is thus 120 - 72 = 48 students.

Now what do we know again? 1/3 of those who stayed behind didn’t want to go. The number that didn’t want to go is thus 1/3 of 48 = 16. The number that wanted to go but didn’t leave with the first batch is thus 48 - 16 = 32

Now, a bus came along and half of those who wanted to go but were left behind joined. This is equal to a value of 1/2 * 32 = 16

Now the question is what fraction of the class left for the field trip. All we need do is add the first batch to the second batch and divide the result by the total number of students. The addition of both yields = 72 + 16 = 88 students.

The fraction that left was thus 88/120 = 11/15

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