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vodka [1.7K]
1 year ago
10

I believe you need to use the quadratic formula for this one, but I am not sure!

Mathematics
1 answer:
Nataly [62]1 year ago
6 0
4x^2+13=49

To solve the value of x in the above equation, here are the steps.

1. Subtract 13 on both sides of the equation.

\begin{gathered} 4x^2+13-13=49-13 \\ 4x^2=36 \end{gathered}

2. Divide both sides of the equation by 4.

\begin{gathered} \frac{4x^2}{4}=\frac{36}{4} \\ x^2=9 \end{gathered}

3. Get the square root on both sides of the equation.

\begin{gathered} \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}

The possible values of x are +3 and -3. The smaller value is -3.

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Which could be the entire interval over which the function,
Marrrta [24]

Answer:

(-2, 1)

Step-by-step explanation:

Hi Juliadayx! How are you?

Well, maybe you already heard about the domain and the range of a function.  

The domain is the set of values that the independent variable can take (usually referred to as the letter "x"), while the range is the set of values that the dependent variable takes, which is called f(x) or function of x.

In this case, the exercise asks you to evaluate for which values of “x” (right column of the table), the function “f(x)” takes positive values (left column of the table), the positive values also include zero. And in this case you can see that the function f(x) is only positive for the values of "x": -2, -1, 0 and 1. Therefore, the answer is the entire interval (-2, 1).

I hope I've been helpful!

Regards!

3 0
3 years ago
An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining.
Tanya [424]

Answer:

98%  Confidencce Interval is ( 3030.6, 7467.4 )

Step-by-step explanation:

Given that:

Sample size n_1 = 71

Sample size n_2 = 31

Sample mean \overline x_1 = 41628

Sample mean x_2 = 36,379

Population standard deviation \sigma_1 = 4934

Population standard deviation \sigma_2 = 4180

At 98% confidence interval level, the level of significcance = 1 - 0.98 = 0.02

Critical value at z_{0.02/2} = 2.33

The Margin of Error = z \times \sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2} }

= 2.33 \times \sqrt{\dfrac{4934^2}{71}+\dfrac{4180^2}{31} }

= 2.33 \times \sqrt{\dfrac{24344356}{71}+\dfrac{17472400}{31} }

= 2.33 \times \sqrt{906504.06 }

= 2218.40

The Lower limit = ( \overline x_1 - \overline x_2) - (Margin \ of \ error)

= ( 41628 - 36379 ) - ( 2218.40)

= 5249 - 2218.40

= 3030.6

The upper limit = ( \overline x_1 - \overline x_2) + (Margin \ of \ error)

= ( 41628 - 36379 ) + ( 2218.40)

= 5249 + 2218.40

= 7467.4

∴  98%  Confidencce Interval is ( 3030.6, 7467.4 )

5 0
3 years ago
Answer asap pllsssssss​
Eva8 [605]

Answer:

the answer is 21x+11

Step-by-step explanation: hope this helps

5 0
2 years ago
Read 2 more answers
What is the value of b?​
koban [17]

Answer:

b=24

Step-by-step explanation:

VT^2 + (2b)^2 = 67^2

VT^2 + (b+24)^2 = 67^2

-> (2b)^2 = (b+24)^2

-> 2b = b+ 24

-> b = 24

8 0
3 years ago
Read 2 more answers
Please help! true or false irrational numbers are not real numbers
valkas [14]

Even Irrational numbers are real numbers. So the question is false.

5 0
2 years ago
Read 2 more answers
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