Area of Trapezoid = (1/2) * (Sum of bases) * height
Area = (1/2) * (11 + 14) * 10
= (1/2) * 25 * 10 = 5 *25 = 125
Area = 125 m²
The answer is 2x15 which is 30ft
Answer:
<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>
Step-by-step explanation:
You observe the problem from a graphical perspective with the image attached.
Notice that side 
is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.
We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.
The hypothenuse is 3959 + 15.6 = 3974.6 mi.
Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.
Answer:
If we do square on both sides we get two answers i.e. (x+12)^2=(3x+20)^2
(x^2)+24x+144=(9x^2)+120x+400
(8x^2)+96x+256=0
(x^2)+12x+32=0
(x+4)(x+8)=0
x= -4 or x= -8.
Else we have another method
x+12=3x+20
x+12–20=3x
x-8=3x,
Now square on both sides.
(x-8)^2=(3x)^2
x^2–16x+64=(9x^2)
(9x^2)-(x^2)+16x-64=0
(8x^2)+16x-64=0
(x^2)+2x-8=0
(x+4)(x-2)=0
x= -4 or x= 2.
But It Didn’t Satisfy for The Equation When
x=2 or x= -8,So The Value of x will be -4 which satisfies given question.
if there is any doubt leave a comment
