2.) coal is the correct answer!
Answer:
Anode:
3Mg(s) ----------> 3Mg2+(aq) + 6e
Cathode:
2Al3+(aq) +6e ---------> 2Al(s)
Explanation:
Anode:
3Mg(s) ----------> 3Mg2+(aq) + 6e
Cathode:
2Al3+(aq) +6e ---------> 2Al(s)
Magnesium is more electro positive than aluminum hence it functions as the anode. Six electrons are lost/gained in the redox process as shown in the oxidation and reduction half reaction equations above. Magnesium is oxidized to magnesium ion while aluminum is reduced to elemental aluminum.
So you need to put numbers before each compound to make sure there are the exact same number of elements on each side. If you put a 4 before NH4 there are 4 Nitrogen and now 16 hydrogen. I just played around with numbers and guessed until I got them even.
Answer:
The answer is given below
Explanation:
When electronegativity difference arises between the bonded atoms, then a molecule is polar.
When electros are shared equally between the bonded atoms or when the polar bonds in a bigger molecule cancels out each other, then a a molucule is non polar.
(a) 50% isopropanol/H2O,--- 2 (second least polar)
(b) 25% isopropanol/H2O,----- 3 (third least polar)
(c) pure water----- is 4 (most polar)
(d) 70% isopropanol/H2O. 1 (least polar)
Explanation:
Reaction equations for the given species is as follows.
At the first equivalence point we need 2 × 10 mmol NaOH.
At the second equivalence point we need 5 mmol of NaOH.
Hence, total moles of NaOH required is as follows.
(20 + 5) mmol = 25 mmol
We assume that volume of NaOH required is V.
= 250 ml V
Thus, we can conclude that 250 ml of 0.10 M NaOH must be added to reach second equivalence point of the titration of the 
and NaOH.
