Use Boyle's Law to solve this problem: A gas has a volume of 10.0 L at a pressure of 4.0 atm. If the gas expands to 20.0 L, what
will be the new volume, assuming that there is no change in moles or temperature.
1 answer:
Answer:
P₂ = 2 atm
Explanation:
Given data:
Initial volume = 10.0 L
Initial pressure = 4.0 atm
Final volume = 20.0 L
Final pressure = ?
Solution:
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
4.0 atm × 10.0 L = P₂ × 20.0 L
P₂ = 40.0 atm. L/ 20.0 L
P₂ = 2 atm
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<h3>Explanation</h3>
Units of each quantity:
- <em>P</em> = 28 atm;
- <em>V</em> = 0.045 L;
- <em>n</em> = 0.020 mol;
Ideal gas constant:
.
Apply the ideal gas law:
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All data given in this question come with two significant figures. Round the value of <em>T</em> to two significant figures:
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