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Komok [63]
3 years ago
15

Which of the following is a cycloalkane?​

Chemistry
2 answers:
hodyreva [135]3 years ago
7 0

Answer:

a

Explanation:

stich3 [128]3 years ago
4 0

Answer:

cyclopentane cyclobutene cyclohexane cycloheptane

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Compare which element would have larger first ionization energy: an alkali metal in Period 2 or an alkali metal in Period 4?
maria [59]

Answer:

An alkali metal present in period 2 have larger first ionization energy.

Explanation:

Ionization energy:

The amount of energy required to remove the electron from the atom is called ionization energy.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.  Thus alkali metal present in period 2 have larger ionization energy because of more nuclear attraction as compared to the alkali metal present in period 4.

6 0
3 years ago
For any molecule at the surface the resulting surrounding forces equal zero
Katarina [22]
False is the correct answer
4 0
3 years ago
Read 2 more answers
Who can answer these?
sesenic [268]
For the first one.. the Reactant side is Zn+2HCl produces Zncl2 and H2... and it is balanced too
6 0
3 years ago
The recommended daily allowance (RDA) of the trace metal magnesium is 410 mg/daymg/day for males. Express this quantity in μg/da
Ira Lisetskai [31]

Answer:

410mg/day *\frac{1000 ug}{1 mg}

Recommended daily Amount (RDA) of magnesium is  410,000 μg/day.

Explanation:

There are 1000μg in 1 mg and 1000 mg in 1g

1 mg=1000μg

The Recommended daily Amount (RDA) is 410 mg/day of magnesium. Converting 410 mg/day into μg/day

410mg/day *\frac{1000 ug}{1 mg}

It will become 410,000 μg/day

So Recommended daily Amount (RDA) of magnesium is  410,000 μg/day.

4 0
3 years ago
PLEASE HELP!!!
Inga [223]

Answer:

d=1.5\ g/cm^3

Explanation:

Given that,

The mass of the rock, m = 15 g

The volume of the rock, V = 10 cm³

We need to find the density of the rock. The density of an object is equal to the mass per unit volume such that,

d=\dfrac{m}{V}\\\\d=\dfrac{15\ g}{10\ cm^3}\\\\d=1.5\ g/cm^3

So, the density of the rock is equal to 1.5\ g/cm^3.

3 0
3 years ago
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