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2 years ago

Which student solved their equation incorrectly? (ANSWER QUICK)

Mathematics

1 answer:

Luden [163]2 years ago

4 0

Jess messed up on the equation

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PLEASE HELPPP! I'LL GIVE BRAINLEST

Tema [17]

Answer:

Thats easy C:

2 and 3 at the same time

Step-by-step explanation:

3x2=6 or if you dived 6/2=3

Also one thing when doing markup or profit(I think thats how you spell it if not im srry my spelling is very bad lol) you dived it

Have a good day :D

8 0

2 years ago

Pls answer my last one to Rodney sold 45,612 copies of his book and Beth sold 45,612 x one half copies of her book. Which statem

Elden [556K]

Answer:

its most likely b

hope this helps!

6 0

3 years ago

Determine the quotient of 1 and 1 over 3 divided by 3 over 5.

natita [175]

1 1/3 divided by 3/5= 2 2/9. Hope this helps :)

4 0

3 years ago

Karen rides her bike 4 mi in 20 min. How many miles will she ride in 1 h and 20 min?

Sever21 [200]

The answer is 84 miles

6 0

3 years ago

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

<u>Trigonometric Identities</u>

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

<u>Trigonometric ratios</u>

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$

7 0

2 years ago

Read 2 more answers