find three consecutive odd integers such that the sum of the last two is 15 less than 5 times the first
1 answer:
You might be interested in
Let us denote the smaller even integer by 
.
Then, the next even integer must be
.
To verify, set as any even number, say 
.
Then, the next even integer must be 2 more than this number, i.e.
.
The sum of these two consecutive even integers can be expressed as:
We are told that this sum divided by four is 189.5, i.e.
Multiplying both sides by 4 will reverse the division:
Subtracting 2 from each side will reverse the addition:
Dividing both sides by 2 will reverse the multiplication:
Therefore, the two consecutive integers must be 378 and 380.
Check this:
Then, the next even integer must be
To verify, set
Then, the next even integer must be 2 more than this number, i.e.
The sum of these two consecutive even integers can be expressed as:
We are told that this sum divided by four is 189.5, i.e.
Multiplying both sides by 4 will reverse the division:
Subtracting 2 from each side will reverse the addition:
Dividing both sides by 2 will reverse the multiplication:
Therefore, the two consecutive integers must be 378 and 380.
Check this: