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ahrayia [7]
2 years ago
10

7x+3 find x. I am confused I need help………………….

Mathematics
2 answers:
ad-work [718]2 years ago
4 0
Dose it have what 7x + 3 is equal to
As this is incomplete
Dahasolnce [82]2 years ago
3 0
Is there more to this, I can’t really help you with this information
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An alloy is 3/8 copper, 5/12 zinc, and the balance lead. How much lead is there in 282 pounds of alloy?
Over [174]
Hope it helps mark me brainlist please

4 0
3 years ago
Can someone please help me with this problem ASAP thank you
Step2247 [10]

3-degree polynomial is f(x )= [x^{3 }-\frac{9}{7} x^{2}+9x-\frac{81}{7} ]

Step-by-step explanation:

Given that polynomial f(x) is 3-degree polynomial and Zeros/Roots at x= \frac{9}{7} and x= -3i

In order to find the equation of a 3-degree polynomial, we need 3 roots.

Here, One of Root is real number x=\frac{9}{7} and another root is an imaginary number x=(-3i)

It is necessary to note that imaginary roots always come in pair of conjugates

Therefore, Comjugate0 of x =(-3i) is 3rd root

Conjugate of (-3i) is 3i

Evaluting equation of polynomial,

=[x-3i][x+3i][x-\frac{9}{7} ]

=[x^{2}-(3i)^{2}][x-\frac{9}{7} ]

=[x^{2}-(9)(i)^{2}][x-\frac{9}{7} ]

=[x^{2}+9][x-\frac{9}{7} ]

f(x )= [x^{3 }-\frac{9}{7} x^{2}+9x-\frac{81}{7} ]

6 0
3 years ago
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
4 years ago
Glenna says that the height of her house is 1 yard is her claim reasonable
muminat
No, her answer is not reasonable because one yard is equal to 3 feet.
4 0
3 years ago
Read 2 more answers
Don and Sally are selling tickets for their school play. Floor seats cost $7.50 and balcony seats cost $5.00. Sally sells 60 flo
oksano4ka [1.4K]

I believe D is the answer.

4 0
3 years ago
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