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3 years ago

Please help me. I bad brain

Mathematics

2 answers:

icang [17]3 years ago

5 0

Answer:

The third X is 6. The fourth Y is 4.5

Step-by-step explanation:

The Rule : X is twice as large as Y. Y is half the size of X.

You can get this piece of information by looking at the different values.

For example, y=1 is x=2. This follows the rule. x=4 is y=2.

We have confirmed the rule is true, now we just need to carry the information into the other blocks!

Best of luck on the quiz! Please give brainliest if I helped you out!

beks73 [17]3 years ago

5 0

Answer: the first row is 6 and the bottom row is 4.5

Step-by-step explanation:

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Given:

The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function

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Solution:

To get defined output, the height h(t) need to be greater than or equal to zero. We need to set up an inequality and solve it to find the domain values.

$To \; find \; domain:\\\\h(t) \geq0\\\\-16t^2+96t \geq 0\\Factoring \; -16t \; in \; the \; left \; side \; of \; the \; inequality\\\\-16t(t-6) \geq 0\\Step \; 1: Find \; Boundary \; Points \; by \; setting \; up \; above \; inequality \; to \; zero.\\\\t(t-6)=0\\Use \; zero \; factor \; property \; to \; solve\\\\t=0 \; (or) \; t = 6\\\\Step \; 2: \; List \; the \; possible \; solution \; interval \; using \; boundary \; points\\(- \infty,0], \; [0, 6], \& [6, \infty)$

$Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq 0\\-112 \geq 0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq 0\\80 \geq 0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq 0\\-112 \geq 0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution$

Conclusion:

The domain of the function is the time in between 0 to 6 seconds

$0 \leq t \leq 6$

The height will be positive in the above interval.

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