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Ostrovityanka [42]

2 years ago

12

Fill in the table find the rule

1 answer:

lakkis [162]2 years ago

8 0

Answer:

I'm sorry but where's the picture

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How do you write 5y<3 without exponents?

satela [25.4K]

Answer:

When an exponent is 1, the base remains the same. a 1 = a . When an exponent is 0, the result of the exponentiation of any base will always be 1, although some debate surrounds 0 0 being 1 or undefined. For many applications, defining 0 0 as 1 is convenient.. a 0 = 1 . Shown below is an example of an argument for a 0 =1 using one of the previously mentioned exponent laws.

Step-by-step explanation:

4 0

3 years ago

Find the missing lengths of the sides.

Anarel [89]

Given:

The figure of a right angle triangle.

$a=b$

Hypotenuse = $9\sqrt{2}$ in.

To find:

The missing lengths of the sides.

Solution:

In the given right angle triangle both legs a and b are equal, and hypotenuse is $9\sqrt{2}$ in.

Using Pythagoras theorem, we get

$Hyponteuse^2=Base^2+Perpendicular^2$

$(9\sqrt{2})^2=(a)^2+(b)^2$

$81(2)=(a)^2+(a)^2$ $[\because a=b]$

$81(2)=2(a)^2$

Divide both sides by 2.

$81=(a)^2$

Taking square root on both sides.

$\pm \sqrt{81}=a$

$\pm 9=a$

Side cannot be negative. So,

$9=a$

Thus, the missing side lengths are a=9 in and b=9 in.

Therefore, the correct option is C.

6 0

3 years ago

What is an equation of the line that passes through the point (-1, 4) and is parallel

alexgriva [62]

Answer: y = 2

Step-by-step explanation:

5 0

2 years ago

Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2

Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

<u>Quadratic Formula</u>

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

<u>Given quadratic equation</u>:

$5x^2-6x-2=0$

<u>Define the variables</u>:

a = 5
b = -6
c = -2

<u>Substitute</u> the defined variables into the quadratic formula and <u>solve for x</u>:

$\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}$

$\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{76}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}$

$\implies x=\dfrac{6 \pm2\sqrt{19}}{10}$

$\implies x=\dfrac{3 \pm \sqrt{19}}{5}$

Therefore, the exact solutions to the given <u>quadratic equation</u> are:

$x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}$

Learn more about the quadratic formula here:

brainly.com/question/28105589

brainly.com/question/27953354

3 0

2 years ago

Read 2 more answers

Saturday, nola bowled 3 games in her bowling league. she had a mean score of 115. the score of her first game was 110. the score

Elina [12.6K]

110+90+145=345
345 divided by 3=115

so the score of her third game was 145 points.
hope i helped! :)
please rate brainliest!

7 0

3 years ago

Read 2 more answers