If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:

Referring to a standard normal distribution table, and using z = 0.66, we find:

Therefore

The answer is: 0.2546
Answer:
y = -2/3x + 3
Step-by-step explanation:
y = -2/3x + b
5 = -2/3(-3) + b
5 = 2 + b
3 = b
Hey i hope my answer is helpful i did in my head so im sorry if its wrong−13 13/35
V = lwh
V = (x + 2)(x + 3)(x)
V = (x)(x^2 + 3x + 2x + 6)
V = (x^3 + 3x^2 + 2x^2 + 6x)
V = x^3 + 5x^2 + 6x
All you do is foil the dimensions together and then combine like terms. Hope this helps!