So we have 299790000, we want to have only one digit in front of the decimal, 2.9979x10^9
hope this helps :)
The value of the z statistic for the considered data is given by: Option A: -3.87 approximately.
<h3>How to find the z score (z statistic) for the sample mean?</h3>
If we're given that:
- Sample mean =
- Sample size = n
- Population mean =
- Sample standard deviation = s
Then, we get:
If the sample standard deviation is not given, then we can estimate it(in some cases) by:
where 
population standard deviation
For this case, we're specified that:
- Sample mean = = 2.3
- Sample size = n = 15
- Population mean = = 2.7
- Population standard deviation = = 0.4
Thus, the value of the z-statistic is evaluated as:
Thus, the value of the z statistic for the considered data is given by: Option A: -3.87 approximately.
Learn more about z statistic here:
brainly.com/question/27003351
<em><u>Complete Question:</u></em>
A colony of flowers is pollinated by hummingbirds and sunbirds. Let H represents the number of hummingbirds and S represent the number of sunbirds that must pollinate the colony so it can survive until next year.
6H+ 4S> 74
This year, 8 hummingbirds pollinated the colony. What is the least number of sun birds that must pollinate the colony to ensure that it will survive until next year?
<em><u>Answer:</u></em>
The least number of sun birds is 7
<em><u>Solution:</u></em>
Given inequality is:
6H + 4S > 74
Where,
H is the number of hummingbirds
S is the number of sunbirds
This year, 8 hummingbirds pollinated the colony
Substitute H = 8 in given inequality
6(8) + 4S > 74
48 + 4S > 74
Subtract 48 from both sides
48 + 4S - 48 > 74 - 48
4S > 26
Divide both sides by 4
S > 6.5
Hence the least number of sun birds is 7
Let's actually find the line of best fit...
m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)
m=(11*836-130*55)/(11*385-3025)
m=2046/1210
m=93/55
b=(Σy-93Σx/55)/n
b=(55Σy-93Σx)/(55n)
b=(7150-5115)/(55*11)
b=185/55, so the line of best fit is:
y=(93x+185)/55
A) The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.
Which means that those who do not practice at all will win about 3.36 times
B) y(13)=(93x+185)/55
y(13)≈25.34
So after 13 months of practice one would expect to win about 25.34 times.
That’s true!!!! They totally should do that!
