Epsom salt is MgSO4.
We assume x water of hydration in the crystalline form.
Molecular mass of MgSO4 = 24+32+4*16=120
Molecular mass of MgSO4.xH2O = 120+18x
By proportion,
2.000/0.977 = (120+18x)/120
Cross multiply
0.977(120+18x) = 120*2.000
from which we solve for x
17.586x+117.24 = 240
x=122.78/17.586
=6.980
Answer: there are 7 water of hydration in Epsom salt, according to the experiment.
Note: more accurate (proper) results may be obtained by using exact values (3-4 significant figures) in the molecular masses. However, since water of hydration is the nearest integer, using approximate values (to at least two significant figures) suffice.
We did a lab on this.
hydrogen peroxide on a raw liver bubbles up and stinks.
Answer:
Ammonia > Urea > Ammonium nitrate > Ammonium sulphate
Explanation:
Percentage by mass of nitrogen in NH3:
Molar mass of NH3= 17 g/mol
Hence % by mass = 14/17 × 100 = 82.35%
% by mass of NH4NO3
Molar mass of NH4NO3 = 80.043 g/mol
Hence; 28/80.043 × 100 = 34.98%
% by mass of (NH4)2SO4;
Molar mass of (NH4)2SO4= 132.14 g/mol
Hence; 28/132.14 × 100 = 21.19%
% by mass of CH4N2O
Molar mass of urea = 60.0553 g/mol
Hence 28/60.0553 × 100 = 46.62%
Answer:
Explanation:
Let final temperature be T .
vapor is at 102⁰C
loss of heat by vapor in turning into water at 100⁰C
= 2.6 x 2 x 1.996 + 2.6 x 2260 = 5886.37 J
loss of heat to lower temperature to T
2.6 x 4.186 x ( 100 - T )
1088.36 - 10.88 T
Total heat loss = 5886.37 + 1088.36 - 10.88 T
= 6974.73 - 10.88 T
heat gain by silver to gain temperature from 1⁰C to T⁰C
= 1250 x ( T - 1 ) x .235 = 293.75 T - 293.75
heat gain = heat loss
293.75 T - 293.75 = 6974.73 - 10.88 T
304.63 T = 7268.48
T = 23.86°C .
