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seraphim [82]
3 years ago
5

A carbon atom with 6 protons, 6 electrons, and 6 neutrons would have a mass number of

Chemistry
1 answer:
Nata [24]3 years ago
7 0
12, electrons dont have mass. only protons and neutrons do
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A covalent bond formed when 2 atoms share 6 valence electrons between them is a ______ bond
sleet_krkn [62]
COVALENT BOND IS THE BOND EXISTING BETWEEN 2 ATOMS THAT SHARE 6 ELECTRONS
5 0
3 years ago
During the combustion of methane (CH4), one mole of methane gas combines with two moles of oxygen gas (O2) to produce one mole o
astraxan [27]

Answer:

CH4(g) +2O2____ CO2(g) +2H2O (l)

3 0
3 years ago
Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:
Andru [333]

Answer:

gde

Explanation:

We are attempting to synthesize 1-butyne from 1-chlorobutane. Since 1-chlorobutane is a primary alkyl halide, 1-butene is formed when 1-chlorobutane is reacted with a bulky base such as t -BuOK or t -BuOH in presence of strong heat. This is an E2 reaction.

Secondly, the 1-butene is reacted with bromine in carbon tetrachloride. The vicinal dihalide (1,2-dibromobutane) is formed. This can now undergo further elimination reactions in the presence of sodamide and strong heat to yield 1-butyne which is the desired product. These reactions involve the elimination of the first HBr molecule to give an alkenyl bromide. A second elimination now gives the terminal alkyne.

3 0
3 years ago
A gas occupies 4.30 Liters at STP. What volume does it occupy at 2.56 atm and 302
laiz [17]

Answer:

V₂ = 1.86 L

Explanation:

Given data:

Initial volume = 4.30 L

Initial pressure = 1 atm

Initial temperature = 273.15 K

Final temperature = 302 K

Final volume =  ?

Final pressure = 2.56 atm

Solution:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂ /T₁ P₂

V₂ = 1 atm ×4.30 L × 302 K / 273.15 K × 2.56 atm

V₂ = 1298.6 atm.L.K / 699.26 K.atm

V₂ = 1.86 L

4 0
3 years ago
What is an experimental control
attashe74 [19]

The experimental control is the standard used as a comparison for the experimental groups.


For example, you may be trying to find out how different types of disinfectants affect bacterial growth.  The control group would receive <em>no</em> disinfectant whereas the experimental groups would be the ones on which the disinfectants were tested.


Hope this makes sense!

3 0
4 years ago
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