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2 years ago

A carbon atom with 6 protons, 6 electrons, and 6 neutrons would have a mass number of

Chemistry

1 answer:

Nata [24]2 years ago

7 0

12, electrons dont have mass. only protons and neutrons do

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Is a burning log an exothermic or endothermic event if the log is the system?

denpristay [2]

It would be endothermic because the log is in the system.

6 0

2 years ago

Determine the number of protons and neutrons in an atom of Uranium - 238

Mila [183]

Answer:

146

Explanation:

uranium is 92 and the mass number of the isotope is given as a 238 therefore it is not the two protons 92 electrons and

real explanation Google it

7 0

2 years ago

Indicate the correct number of sig figs

Dimas [21]

Explanation:

The answer to questions are

A) 4

B) 3

C) 5

D) 3

E) 3

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2 years ago

The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma

Pavlova-9 [17]

Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C= $p_o= 187.54 mmHg$

Vapor pressure of the solution at 65 °C= $p_s$

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water= $n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol$

Moles of ethylene glycol= $n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol$

$\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}$

$\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}$

$p_s=173.83 mmHg$

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

6 0

2 years ago

Oxygen always has an oxidation number of -2 unless it is combined with fluorine or found in the compound peroxide. When in the c

Tpy6a [65]

When oxygen is found is peroxide, it has an oxidation number of -1.

The chemical formula of hydrogen peroxide is H2O2. We know that hydrogen always has +1 oxidation state until it forms metal hydrides. So in H2O2, the oxidation state ofhydrogen is +1.

Now, let oxidation state of oxygen be x. So,

2 * (+1) + 2*x = 0

2 + 2x = 0

2x = -2

x = -2 / 2

x = -1

Hence, the oxidation number of oxygen in peroxides is -1

6 0

2 years ago