Answer:
7505÷11 = 682.27272727
Step-by-step explanation:
or you can just put a line over the 27
For the answer to the question above, the slope of segment AC is (-6/22) = -3/11.
The slopes of perpendicular lines are negative reciprocals, so
you know that the slope of the perpendicular bisector will be 11/3.
The midpoint of segment AC is (7, -5).
Now you have the slope of the perpendicular bisector, and a
point on it. You should be able to complete the equation now.
Notice how sneaky this question is. You don't need to know
point-B at all, and you don't even need to know that there's
any triangle. All you need to know is points A and C.
Answer:
-136
Step-by-step explanation:
This series can be written as: (14 - 3*0) + (14 - 3*1) +...+ (14 - 3*n)
The sum of the first 16 terms is:
14*16 <u>- 0 - 3 - 6 - 9 -...</u> = 224 - 360 = -136
This underlined bit can be calculated in many ways, I personally used my calculator, but there are formulas to do so.
Circle equation: (x - h) + (x - k) = r²
(h, k) = center
r = radius
The center is (-7, 4)
To find the radius, take the square root of 49.
√49 = 7
The radius is 7.
Best of Luck!
When you cut off for squares of x side length, the area of the base of the box is [10 - 2x]^2 and the height ot the box is x, then the volumen of the box is:
(10 - 2x)^2 * x = 48
(100 - 40x + 4x^2)*x = 48
100x - 40x^2 + 4x^3 = 48
4x^3 - 40x^2 + 100x - 48 = 0
x^3 - 10x^2 + 25x - 12 = 0
Using Ruffini you can get 3 as a solutio:
3^3 - 10(3^2) + 25(3) - 12 = 27 - 90 + 75 - 12 = 0
Factoring you get (x - 3) (x^2 -7x + 4) = 0
Then, you can apply the quadratic formula to x^2 -7x + 4 to find the other two roots.
They are x = 0.6277 and x = 6.3723.
x = 6.32723 is not valid because 10 - 2x < 0.
Then there are two real solutcions for the side of the squate: 3 and 0.6277 (althoug the second one is a very low box)
