The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.
sec(<em>x</em>) = csc(<em>x</em>)
By definition of secant and cosecant,
1/cos(<em>x</em>) = 1/sin(<em>x</em>)
Multiply both sides by sin(<em>x</em>) :
sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)
As long as sin(<em>x</em>) ≠ 0, this reduces to
sin(<em>x</em>)/cos(<em>x</em>) = 1
By definition of tangent,
tan(<em>x</em>) = 1
Solve for <em>x</em> :
<em>x</em> = arctan(1) + <em>nπ</em>
<em>x</em> = <em>π</em>/4 + <em>nπ</em>
(where <em>n</em> is any integer)
In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of
<em>x</em> = <em>π</em>/4 <u>or</u> <em>x</em> = 5<em>π</em>/4
Answer:
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. 16)n = 182, x = 135; 95 percent
✓ 16)n = 182, x = 135; 95 percent sample proportion: p-hat = 135/182 = 0.74 E = 1.96*sqrt[0.74*0.26/182] = 0.0637 95% CI: 0.74-0.0637 < p < …
So every 5 inches in height, there are 32 marbles. You want to know how many marbles there are per 18 inches in height.
To get from 5 to 18, you multiply by 3.6.
Do the same thing to the numerator; 32 × 3.6 = 115.2.
Since 0.2 marbles is no marbles, you round down.
There are 115 marbles in the box.
♡ Hope this helps! ♡
❀ 0ranges ❀
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For all the dogs: you have 2.65+2.46+3.67+2.91 = 11.69%
Now, the probability of getting a chihuahua would be 3.44/11.69=0.2942= 24.92
Step-by-step explanation:
there ya go!!
