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2 years ago

What is the IQR for the data set? {31, 30, 40, 35, 48, 44, 25} Drag and drop the correct answer into the box.

Mathematics

1 answer:

Kitty [74]2 years ago

4 0

Answer:

Step-by-step explanation:

IQR is the higher qurtile subtracted by the lower qurtile so higher is 40 and lower is 20 so 14

Hope this helps have a great day:)

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From a July 2019 survey of 1186 randomly selected Americans ages 18-29, it was discovered that 248 of them vaped (used an e-ciga

jasenka [17]

Answer:

The 90% confidence interval is (0.1897, 0.2285).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

From a July 2019 survey of 1186 randomly selected Americans ages 18-29, it was discovered that 248 of them vaped (used an e-cigarette) in the past week. This means that $n = 1186, \pi = \frac{248}{1186} = 0.2091$

Construct a 90% confidence interval to estimate the population proportion of Americans age 18-29 who vaped in the past week.

So $\alpha = 0.10$ , z is the value of Z that has a pvalue of $1 - \frac{0.10}{2} = 0.95$ , so $z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2091 - 1.645\sqrt{\frac{0.2091*0.7909}{1186}} = 0.1897$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2091 + 1.645\sqrt{\frac{0.2091*0.7909}= 0.2285$

The 90% confidence interval is (0.1897, 0.2285).

3 0

3 years ago

1. Kristen spent $131 on shirts at Target last week. She bought some fancy shirts for

Masja [62]

Answer:

Kristen bought 2 fancy shirts and 5 plain t-shirts.

Step-by-step explanation:

Given that,

Kristen spent $131 on 7 shirts.

Cost of one fancy shirt = $28

Cost of one plain t-shirt = $15

Let,

x be the number of fancy shirts

y be the number of plain t-shirts

x+y = 7 Eqn 1

28x+15y=131 Eqn 2

Multiplying Eqn 1 by 15

15(x+y=7)

15x+15y=105 Eqn 3

Subtracting Eqn 3 from Eqn 2

(28x+15y)-(15x+15y)=131-105

28x+15y-15x+15y=26

13x=26

Dividing both sides by 13

$\frac{13x}{13}=\frac{26}{13}\\x=2$

Putting x=2 in Eqn 1

2+y=7

y=7-2

y=5

Hence,

Kristen bought 2 fancy shirts and 5 plain t-shirts.

3 0

3 years ago

Which description best fits the distribution of the data shown in the histogram?

s344n2d4d5 [400]

This is an approximately bell-shaped distribution. The highest bar is in the center, with height = 12. Just to its left and right are bars of heights 6 and 5. At the extremes are bars of heights 2 and 1.

If the highest bar was on the left, it would be skewed left (and if it was on the right, skewed right). A uniform distribution would more or less have the same height level over all the bars.

5 0

3 years ago

Read 2 more answers

Can someone please answer this for me.

Levart [38]

Answer:

See picture

Step-by-step explanation:

The rule is ...

$x^{m/n}=\sqrt[n]{x^m}$