Answer:
Explanation:
The index of refraction is equal to the speed of light c in vacuum divided by its speed v in a substance, or 
. For our case we want to use 
, which for our values is equal to:
Which we will express with 3 significant figures (since a product or quotient must contain the same number of significant figures as the measurement with the <em>least</em> number of significant figures):
Answer:
The correct answer is
d. heating evaporative cooling and mineral transport
Explanation:
Plants transpire to expel excess heat energy by a process known as evaporative cooling. As the water involved in transpiration evaporates, heat energy is transferred from the plant system into the surrounding environment cooling down the plant.
During transpiration, the stomata of the plant are open allowing the outward flow of the evaporated water and also the open stomata enable the plant to absorb carbon dioxide (CO2) from the atmosphere. The carbon dioxide is required in photosynthesis for the formation glucose while producing oxygen as well.
The water also transports nutrients dissolved in it as it is being transported to the leafs for evaporation. These nutrients are thus delivered tm all parts of the plant.
Answer:
D = 271.54 m
Explanation:
given,
1. car accelerates at 4.6 m/s² for 6.2 s
2. constant speed for 2.1 s
3. slows down at 3.3 m/s²
distance travel for case 1
using equation of motion
d₁ = 88.41 m
case 2
constant speed for 2.1 s now, we have to find velocity
v = u + at
v = 0 + 4.6 x 6.2
v = 28.52 m/s
distance travel in case 2
d₂ = v x t
d₂ = 28.52 x 2.1 = 59.89 m
for case 3
distance travel by the car
v² = u² + 2 a s
final velocity if the car is zero
0² = 28.52² + 2 x (-3.3) x d₃
6.6 d₃ = 813.39
d₃ = 123.24 m
total distance travel by the car
D = d₁ + d₂ + d₃
D = 88.41 + 59.89 + 123.24
D = 271.54 m
Answer:
1 going from a gas to a liquid
2 longitudinal waves
3 longitudinal waves
4 transverse waves
I can guarantee you that it is not
C.<span>the angle that the incident ray makes with a line drawn perpendicular to the reflecting surface I hope this somewhat helps</span>
