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Bas_tet [7]
3 years ago
6

The water lost during transpiration is a side effect of the plant’s exchange of gases. However, the plant derives some benefit f

rom this water loss in the form of _____. aa. increased turgor and increased growth b. increased growth and metabolic c. heating evaporative cooling and metabolic d. heating evaporative cooling and mineral transport
Physics
1 answer:
madam [21]3 years ago
5 0

Answer:

The correct answer is

d. heating evaporative cooling and mineral transport

Explanation:

Plants transpire to expel excess heat energy by a process known as evaporative cooling. As the water involved in transpiration evaporates, heat energy is transferred from the plant system into the surrounding environment cooling down the plant.

During transpiration, the stomata of the plant are open allowing the outward flow of the evaporated water and also the open stomata enable the plant to absorb carbon dioxide (CO2) from the atmosphere. The carbon dioxide is required in photosynthesis for the formation glucose while producing oxygen as well.

The water also transports nutrients dissolved in it as it is being transported to the leafs for evaporation. These nutrients are thus delivered tm all parts of the plant.

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An ant crawls 50 cm to the right, stops, and then crawls 30 cm to the left. Calculate the distance that the ant travels, and cal
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Answer and Explanation:

If the ant was to crawl 50cm to the right, then come back 30 cm, then the total distance walked would be <u>80cm</u>.

- Combine 50cm and 30cm to get 80 cm.

For displacement, the answer is <u>20 cm.</u>

- When calculating displacement, you use the initial (starting) distance. and subtract that from the final distance, giving you the displacement, or the amount traveled from the starting point to the final point if you were to make a straight line from the starting point to end point. (0 to 50, then back 30 the same direction, so subtract 30 from 50 to get 20)

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8 0
3 years ago
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A 2.5m long steel piano wire has a diameter of 0.5cm how great is the tention in the wire if it stretches by 0.45cm when tighten
UkoKoshka [18]

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Explanation:

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7 0
3 years ago
Calculate the pressure exerted by 11.1 moles of neon gas in a volume of 5.45 L at 25°C using (a) the ideal gas equation and (b)
Ilia_Sergeevich [38]

Answer:

49.82414 atm

50.74675 atm

Explanation:

P = Pressure

V = Volume = 5.45 L

R = Gas constant = 0.08205 L atm/mol K

T = Temperature = 25°C

a = 0.211 atm L²/mol²

b = 0.0171 atm L²/mol²

From ideal gas law we have

PV=nRT\\\Rightarrow P=\dfrac{nRT}{V}\\\Rightarrow P=\dfrac{11.1\times 0.08205(273.15+25)}{5.45}\\\Rightarrow P=49.82414\ atm

The pressure is 49.82414 atm

From Van der Waals equation we have

\left(P+\frac{an^2}{V^2}\right)\left(v-nb\right)=nRT\\\Rightarrow P=\dfrac{nRT}{V-nb}-\dfrac{an^2}{V^2}\\\Rightarrow P=\dfrac{11.1\times 0.08205\times (273.15+25)}{5.45-(11.1\times 0.0171)}-\dfrac{0.211\times 11.1^2}{5.45^2}\\\Rightarrow P=50.74675\ atm

The pressure is 50.74675 atm

3 0
3 years ago
The push up is dynamic or static​
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Answer:

Dynamic exercises

Explanation:

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