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Bas_tet [7]
3 years ago
6

The water lost during transpiration is a side effect of the plant’s exchange of gases. However, the plant derives some benefit f

rom this water loss in the form of _____. aa. increased turgor and increased growth b. increased growth and metabolic c. heating evaporative cooling and metabolic d. heating evaporative cooling and mineral transport
Physics
1 answer:
madam [21]3 years ago
5 0

Answer:

The correct answer is

d. heating evaporative cooling and mineral transport

Explanation:

Plants transpire to expel excess heat energy by a process known as evaporative cooling. As the water involved in transpiration evaporates, heat energy is transferred from the plant system into the surrounding environment cooling down the plant.

During transpiration, the stomata of the plant are open allowing the outward flow of the evaporated water and also the open stomata enable the plant to absorb carbon dioxide (CO2) from the atmosphere. The carbon dioxide is required in photosynthesis for the formation glucose while producing oxygen as well.

The water also transports nutrients dissolved in it as it is being transported to the leafs for evaporation. These nutrients are thus delivered tm all parts of the plant.

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Why concave lens is called diverging lens​
dangina [55]

When a parallel beam of light passes through a convex lens, the rays become farther from one another when the come out. This process of rays is called ''to diverge''. The concave lens makes rays of light diverge, so it is called diverging lens.

6 0
2 years ago
Can someone help me please??
Mrrafil [7]

1. Our solar system is the only place in the universe where gravity played a key part in the formation of planets.

2. Rocky planets are small, dense, and orbit relatively close to the sun, compared to the Jovian planets, which are large, less dense, and orbiting far from the sun.

3. _______

7 0
3 years ago
A 13-kg sled is moving at a speed of 3.0 m/s. At which of the following speeds will the sled have twice as much kinetic energy?
AysviL [449]
K.E. = 1/2 mv²
K.E. is directly proportional to v^2
So, when K.E. increase by 2, K.E. increase by root. 2
v' = 1.41v
original v value was 3 so, final would be:
v' = 1.41*3 = 4.23
After round-off to it's tenth value, it will be:
v' = 4.2

So, option B is your answer!

Hope this helps!

7 0
3 years ago
A block of mass 10.0 kg is pulled to the right along a rough horizontal surface with a constant horizontal force of 20.0 N. The
Yakvenalex [24]

Answer:

the magnitude of acceleration will be 1.50m/s^2

Explanation:

To calculate your acceleration, you can use your formula that states that the net force on an object is equal to the mass of the object multiplied by the acceleration of the object. Fnet=ma

if you draw out this situation and label the forces you will have your vector towards the right with a magnitude of 20.0N and then your friction vector will be pointing to the left (in other words, in the negative direction) (opposing the direction of movement) with a magnitude of 5.00N, with the 10.0 kg box in the middle.

The net force will be calculated using F1+F2=Fnet where your F1=20.0N and F2= -5.00N (since it is towards the negative direction).

you will find that Fnet=15.0N

With that, plug in the values you know to calculate the acceleration of the block:

Fnet=ma

(15.0N)=(10.0kg)a    from her you can divide both sides by 10 to isolate a:

1.50=a  (and now make sure to label the units of your answer)

a=1.50m/s^2 (which is the typical unit for acceleration)

7 0
2 years ago
Which positions experience low tide
MrMuchimi

Answer:

lentic zones because they do not move they are stagnant water examples are ponds, swap, dams.

8 0
3 years ago
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