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Lyrx [107]
4 years ago
14

As a transverse wave travels through a rope from left to right, the parts of the rope _______.

Physics
1 answer:
kupik [55]4 years ago
8 0
<h3><u>Answer;</u></h3>

Are moving up and down.

As a transverse wave travels through a rope from left to right, the parts of the rope <u>are moving up and down</u>.

<h3><u>Explanation;</u></h3>
  • Transverse waves occur when a disturbance causes oscillations perpendicular to the propagation, that is the direction of energy transfer.
  • <em><u>Particles of the medium move perpendicular to the direction the transverse wave itself is moving.  For example, if the wave is moving to the right, the particles of the medium are moving up and down.</u></em>
  • <em><u>Therefore, as a transverse wave travels through a rope from left to right, the parts of the rope are moving up and down.</u></em>
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How is newtons law of motion used for testing the safety of automobile
Colt1911 [192]
Newton's first law of motion is an object in motion stays in motion until acted upon by another force. Driving at 30 mph in a car is going to stay constant until you crash the car into a wall, stopping the car.
3 0
3 years ago
You have a source of energy containing 21 gj of energy at 600k how much this energy can be converted to work when rejecting heat
sweet [91]

Answer:

Available energy = 35 x 10⁶ J

Explanation:

Given:

Amount of energy (Q) = 21 gj = 21 x 10⁹ J

Temperature T1 = 600 k

Temperature T0 = 27 + 273 = 300k

Find:

Available energy

Computation:

Available energy = Q[1/T0 - 1/T1]

Available energy = 21 x 10⁹ J[1/300 - 1/600]

Available energy = 35 x 10⁶ J

4 0
3 years ago
A 1.0 kg piece of copper with a specific heat of cCu=390J/(kg⋅K) is placed in 1.0 kg of water with a specific heat of cw=4190J/(
Valentin [98]

Answer:

The temperature change of the copper is greater than the temperature change of the water.

Explanation:

deltaQ = mc(deltaT)

Where,

delta T = change in the temperature

m =mass

c = heat capacity

\frac{(deltaT)_{Cu}}{(deltaT)_{w}}=\frac{4190J/kg.K}{390J/kg.K}\\ \\(deltaT)_{Cu}=10.74(deltaT)_{w}

The temperature change in the copper is nearly 11 times the temperature change in the water.

So, the correct option is,

The temperature change of the copper is greater than the temperature change of the water.

Hope this helps!

7 0
3 years ago
The spool has a mass of 50 kg and a radius of gyration of ko = 0.280 m. if the 20-kg block a is released from rest, determine th
Rzqust [24]
V₁ = (1/g)₁ = Way₁ = 20(9.81)(0) = 0
V₂ (Vg)₂ = -WAy₂ = -20(9.81)(0.5) = -98.1J
The kinetic energy because the pool rotates about a fixed axis 
W = VA/rA = VA/0.2 5VA
Mass momen of inertila about fixed axis which passes through point 0
I₀ = mko² = 50(0.280)² = 3.92 kg. m²
∴ The kinetic energy of the system is 
T = 1/2 I₀w² + 1/2mAVA²

= 1/2(3.92)(5VA)² + 1/2 (20) VA² = 59VA²
Now that the system is at rest then T₁ = 0
Energy conservation  is
T₁ +V₁ = T₂ + V₂
0+ 0 = 59VA² + (-98.1)
VA = 1.289 m/s
= 1.29 m/s
5 0
3 years ago
If spring has a spring constant of 500 N/m and is stretched .50 meters,how much energy is stored in the spring ((show work for f
Free_Kalibri [48]

Answer:

The energy stored is: 62.5 Joules

Explanation:

Given

k = 500N/m --- spring constant

x = 0.5m --- stretch

Required

The amount of energy

This is calculated as:

U = \frac{1}{2} kx^2

U = \frac{1}{2} * 500N/m * (0.5m)^2

U = 250N/m * (0.5m)^2

U = 62.5\ J

7 0
3 years ago
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