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2 years ago

Amy invites 800 people to her pool

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

4 0

Answer:

400

Step-by-step explanation:

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On one of the Tigers’ plays, Terrence thought they went for +3 yards, but his father told him they actually lost three yards. Wh

stealth61 [152]

−1

Explanation:

Let's say the set of downs starts at the 20 yard line (maybe the kicking team kicked deep, the receiving team took a knee and so play starts at the 20).

Ok - we're at the 20. First down - they advance 5 yards. So we're now at the 25. We can write that mathematically as:

20 + 5= 25

So the second play they get sacked deep and lose 6 yards. So we subtract 6:

25 − 6=19

So what's the change in yardage for the 2 plays? We are on the 19 and started at the 20, so we can write:

19 − 20= −1

and this makes sense because we know we advanced 5 and fell back 6:

+5 −6 = −1

3 0

2 years ago

Y = 2x – 4 and y = x – 2

hammer [34]

Step-by-step explanation:

x=2

y=0

.................

7 0

3 years ago

Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3

Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

$\frac{dV}{dt} = -kA$

Using Euler's method

$\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i} \\$

Where initial droplet volume is:

$V(0) = \frac{4pi}{3} * r(0)^3 = \frac{4pi}{3} * 2.5^3 = 65.45 mm^3$

Hence, the iterative solution will be as next:

i = 1, ti = 0, Vi = 65.45

$V'_{i} = -k *4pi*(\frac{3*65.45}{4pi})^(2/3) = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88$

i = 2, ti = 0.5, Vi = 63.88

$V'_{i} = -k *4pi*(\frac{3*63.88}{4pi})^(2/3) = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33$

i = 3, ti = 1, Vi = 62.33

$V'_{i} = -k *4pi*(\frac{3*62.33}{4pi})^(2/3) = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813$

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

$r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\$

The average change of droplet radius with time is:

Δr/Δt = $\frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min$

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0

3 years ago

The number of tickets sold for a concert during each hour ,x, of the first 10hours the tickets were in sale is given by g(x)=x^3

Mashutka [201]

The number in tickets sold A)107

8 0

3 years ago

29 is what percent of 20?

Vanyuwa [196]

29 percent = 29/100
So 29/100 x 20
= 5.8

4 0

2 years ago