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Nookie1986 [14]
2 years ago
6

What is the slope of the line that passes through the points (0,-10) and (-4,-11)? Write your answer in simplest form.

Mathematics
1 answer:
Luda [366]2 years ago
8 0
From formula m= y2-y1 / x2-x1

Solution

-11-(-10) /. -4-0

= -1/-4

Have a nice day
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For the following geometric sequence, find the recursive formula.<br> {-80, 20, -5, ...}
skad [1K]
For the<span> geometric sequence, it has two forms of formula

</span>
<span>We are interested in the recursive formula now

</span>
<span> {-80, 20, -5, ...}

The common ratio is (20/-80)=(-5/20)=-1/4=-0.25

So our r</span><span>ecursive formula would bea_n=a_{n-1}*(-0.25)=a_{n-1}*(- \frac{1}{4} )


</span>

I hope that helps!



3 0
3 years ago
Write an expression with five different terms that is equivalent to 8x^2 + 3x^2 + 3y
Misha Larkins [42]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

An expression having five terms which is equivalent to above term is :

  • 5x {}^{2}  + 3 {x}^{2}  + 3{x}^{2}  +4y - y

3 0
3 years ago
Line segment YV of rectangle YVWX measures 24 units.
Anna [14]

Answer: 8√3

<u>Step-by-step explanation:</u>

ΔXVW is a 30°-60°-90° triangle. This special triangle has corresponding sides of lengths: b - b√3 - 2b.  So,

VW = b

XW = b√3

XV = 2b

Since, YV = 24, then XW = 24 and we stated above that XW = b√3. So,

24 = b√3

\frac{24}{\sqrt{3}} = \frac{b\sqrt{3}}{\sqrt{3}}

\frac{24}{\sqrt{3}} = b

\frac{24}{\sqrt{3}}(\frac{\sqrt{3}}{\sqrt{3}}) = b

\frac{24\sqrt{3}}{3} = b

8√3 = b

We are looking for side YX which is congruent (equal) to VW and we stated above that VW = b, So, VW = 8√3

7 0
3 years ago
PLZZZZ HURRY ILL GIVE BRAINLEST POINTS PLZZZZ I NEED A 100% ON THIS TEST
PSYCHO15rus [73]

Answer:

y=2/3x-1 is 3/2

y=-2/3x-1 is x=3/2

y=-3/2x-1 is x= 2/3

Step-by-step explanation:

3 0
3 years ago
The formula Y=X⁴-4X³+3X² is growing?
miskamm [114]

Answer:

The best way to know weather the formula y=x⁴-4x³+3x² is growing or not, is by graphing it.

As you can see in the attached picture:

  • For -inf<x< 0 the graph decreases.
  • For 0<x<0.634 the graph is growing
  • For 0,634<x<2.366 the graph decreases
  • For 2.366<x<+inf the graph is growing.

Therefore, the polynomial grows in the intervals stated before.

6 0
3 years ago
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