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3 years ago

Whats the answer to this?

Mathematics

2 answers:

USPshnik [31]3 years ago

8 0

Answer:

Sorry I don't know

Step-by-step explanation:

harina [27]3 years ago

6 0

Answer:

6cm

Step-by-step explanation:

I will apply equivalent fractions here or enlargement is also allowed

let find the factor,k

3/0.25=k

12=k

to get x

x/0.5=12

x=12*0.5

x=6cm

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Family bought 12 oranges from the market. However, one-fourth of these oranges were rotten. How many oranges were not rotten?

sashaice [31]

Answer:

1/4 of them were rotten

rotten ones = 1/4 × 12 = 3

ones that weren't rotten = 12 - 3 = 9

4 0

3 years ago

Y=-2(×-3)(x-2) to standard form <br><br>(show work)

damaskus [11]

Answer:

y=-2x^2+10x-12

Step-by-step explanation:

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3 years ago

A plane flew for 2 hours at 467 mph (miles per hour) and 5 hours at 536. How far did the plane fly in miles

Archy [21]

Answer:

3614 miles

Step-by-step explanation:

Given data

A plane flew for 2 hours at 467 mph

Let us find the distance covered

Speed= distance/time

Distance= speed*time

Distance= 467*2

Distance=934 miles

5 hours at 536

Let us find the distance covered

Speed= distance/time

Distance= speed*time

Distance= 536*5

Distance=2680 miles

Total distance

=2680+934

=3614 miles

3 0

3 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

3 years ago

A car has 15 gallons of gas in its tank. The car travels 35 miles per gallon of gas. It uses 1/35 of a gallon of gas to go one m

ikadub [295]

Answer:

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Step-by-step explanation:

If 1/35 gallon of gas = 1 mile

To travel 100 miles,

1/35 × 100

= 0.0286 × 100

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Therefore, the car needs 2.86 gallons of gas to travel 100 miles.

4 0

3 years ago