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Y_Kistochka [10]
3 years ago
5

How does A(x) = 4^x change over the interval from x = 2 to x = 3?

Mathematics
1 answer:
Ivahew [28]3 years ago
3 0

Replace x and solve:


4^2 = 16

4^3 = 64

Now divide the solutions

64/16 = 4


This is an increase of a factor of 4.


ANSWER:

H(x) increases by a factor of 4

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The median for the given set of six ordered data values is 32.5.
klemol [59]

Answer:

59

Step-by-step explanation:

5

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3 years ago
shemillie earns $8 per hour at a yogurt store. she receives a 5% raise. What are her new hourly earingings?
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dalvyx [7]

Answer:

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3 0
3 years ago
Using suitable identity evaluate the following : 98^3
stiv31 [10]

941,192

Steps:

(a-b)^3=a^3-b^3-3a^2b+3ab

\begin{gathered} (98)^3=(100-2)^3 \\ (100-2)^{3\text{ }}=(100)^3-(2)^3-3\cdot(100)^2\cdot2+3\cdot100\cdot2^2\text{ } \\ (100)^3-(2)^3-3\cdot(100)^2\cdot2+3\cdot100\cdot2^2\text{ = 1,0}00,000\text{ - 3 - 60,000 +1,200} \\ \text{ 1,0}00,000\text{ - 3 - 60,000 +1,200 = 941,192} \end{gathered}

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1 year ago
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4 years ago
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