Step-by-step explanation:
1) Your problem → (4x^2 - 17x^3 + 9) - (x^2 + 9x + 23x^2 + 11)
(-17x^3+4x^2+9)-(x^2+23x^2+9x+11)
=-17x^3+4x^2+9-x^2-23x^2-9x-11
=-17x^3+4x^2-x^2-23x^2-9x+9-11
=-17x^3-20x^2-9x-2
2) Your problem → 0 - 19.73 - 25x^2 - 12x - 3
=0-19.73-25x2-12x-3
=-25x^2-12x-22.73
3) - 10.x^3 – 162x^2 – 24x - 4
4) Your problem → 17x^3 - 20x^2 - 9x^2
=17x^3-20x^2-9x^2
=17x^3-29x^2
5) -16x^3 – 243x^2 – 12x – 3
Answer:
1/2
Step-by-step explanation:
It is a independent problem. Flipping a head the first time will not affect the other results therefore it is still one half.
The slope of a line includes a x and y axis, or y/x. Your two answers are -7/4 and -8/5. Hope that helps!
Answer:
z = 61
Step-by-step explanation:
The exterior angle is congruent (equal to) the sum of the 2 farthest angles from it, so you can set the equation like this:
z + z - 11 = z + 50
Add like terms, which would be the 2 "z's" on the left side:
2z - 11 = z + 50
Then subtract the z on the right side from both sides:
2z - 11 = z + 50
-z -z
___________
z - 11 = 50
Add 11 to both sides:
z - 11 = 50
+ 11 +11
________
z = 61
I need to know the rest of the question in order to help you! :D