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lawyer [7]
3 years ago
8

Briana is planning to spend March break at a winter resort. The cost of a 7-day snowboarding pass, including equipment rental, i

s $199. On the resort’s website, Briana reads that a daily pass with no equipment rental is $25.
How much is being charged for renting the equipment for the week?
Mathematics
1 answer:
N76 [4]3 years ago
6 0

Answer:

$24

Step-by-step explanation:

cost of a pass for a week (without equipment rental) = 7 x 25 = $175

Therefore, cost of just renting the equipment for the week = 199 - 175 = $24

ETA: As an algebraic equation

Let x = number of days

Let y = cost of renting the equipment for a week

y = 199 - 25x

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PLEASE HELP DUE AT 8:30 A.M. I WILL MARK BRAINLIEST! Thank you
spayn [35]

Answer:

1. no solution

2. one solution

3. infinitely many solutions

Step-by-step explanation:

1. 4= -3

false

2. -5=6c+7

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3. 5a+7=5a+7

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3 0
3 years ago
Read 2 more answers
What is the value of 11g - 9k + 3 when g = 9 and k = 11?<br> Neatly show your work.
fenix001 [56]

Answer:

3

Step-by-step explanation:

11g - 9k + 3

Let g = 9 and k =11

11 * 9 - 9*11 +3

Multiply

99 - 99 +3

Add

3

4 0
3 years ago
Read 2 more answers
Use the Pythagorean theorem to find the unknown side of the right triangle.
Nesterboy [21]

The length of hypotenuse is 39.

Step-by-step explanation:

Given,

Vertical side = a = 15

Horizontal side = b = 36

Hypotenuse = c

Using pythagorean theorem

a^2+b^2=c^2\\(15)^2+(36)^2=c^2\\225+1296=c^2\\1521=c^2\\c^2=1521

Taking square root on both sides

\sqrt{c^2}=\sqrt{1521}\\c=39

The length of hypotenuse is 39.

Keywords: square root, addition

Learn more about square roots at:

  • brainly.com/question/9196410
  • brainly.com/question/9178881

#LearnwithBrainly

8 0
4 years ago
6,666,666×666,666 /1+2+3+4+5+6+5+4+3+2+1 − 777,777×777,777/1+2+3+4+5+6+7+6+5+4+3+2+1
jeka57 [31]

Answer:

111111 \times 1111110 is the simple expression.

Step-by-step explanation:

The expression to be solved:

\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1} - \dfrac{777,777\times777,777}{1+2+3+4+5+6+7+6+5+4+3+2+1}

First of all, let us solve the first term:

\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1}\\\Rightarrow \dfrac{6666666\times666666 }{36}\\\Rightarrow \dfrac{6666666\times666666 }{6\times 6}\\\Rightarrow 1111111\times 111111

Now, the right term:

\dfrac{777777\times777777}{1+2+3+4+5+6+7+6+5+4+3+2+1}\\\Rightarrow \dfrac{777777\times777777}{49}\\\Rightarrow \dfrac{777777\times777777}{7 \times 7}\\\Rightarrow 111111 \times 111111

So, the expression to be solved becomes:

1111111\times 111111-111111\times 111111\\\Rightarrow 111111(1111111-1)\\\Rightarrow 111111\times 1111110

3 0
3 years ago
I'd like help with the bottom two questions. Thanks! (7 and 8)
BabaBlast [244]

I have the answer for the first question, the second one idk how to do. To solve mean add all the numbers and divide by how many there are. 300/5 = 60 so that is the mean. For standard deviation subtract mean from every number in the list and square it. 225, 100,0, 25, and 225. Average these numbers and you will get the standard deviation of 115. Im sorry I cant do the second question but I hope this helped for the first one.

5 0
3 years ago
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