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Nutka1998 [239]
3 years ago
7

A ratio that compares a quantity to 100 is a/an....

Mathematics
1 answer:
abruzzese [7]3 years ago
3 0

Answer: percent

Step-by-step explanation: 1 out of 100 is 1%

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It takes Jill 2 hours to run 14.5 miles, At this rate, how far could she run in 3 hours? Btw, I am giving a lot of points if you
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Answer:

21.75

Step-by-step explanation:

To find how long she can run in a single mile, divide 14.5 by 2, giving you 7.25. If she runs three of those, (3 times 7.25), she runs 21.75 miles.

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Find the percent increase or decrease from Monday to Tuesday.
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the answer is -75% that mean 75% decrease

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Write the fractions for 9/12
Flauer [41]

9/12 divide by 3 equals 3/4

9/12 x 2 = 18/24

this is the only two things I can show you I hope this helps

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Find equations for the tangent plane and the normal line at point upper p 0​(3 comma 5 comma 0​) on the surface negative 7 cosin
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Dude what the heck......
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3 years ago
Select the pair of equations whose graphs are perpendicular.  
viktelen [127]
k:\ y=m_1x+b_1\ \ \ \ and\ \ \ \ l:\ y=m_2x+b_2\\ \\the\ line\k\ is\ perpendicular\ to\ the\ line\ l\ \ \ \Leftrightarrow\ \ \ m_1\cdot m_2=-1\\----------------------------\\\\A.\\2y=-3x+5\ \ \Rightarrow\ \ \ y=-  \frac{3}{2}  x+2.5\ \ \Rightarrow\ \ m_1=- \frac{3}{2} \\\\2x+3y=4\ \ \Rightarrow\ \ 3y=-2x+4\ \ \Rightarrow\ \ y=- \frac{2}{3}x+1 \frac{1}{3}  \ \ \Rightarrow\ \ m_2=- \frac{2}{3} \\\\m_1\cdot m_2=- \frac{3}{2} \cdot (- \frac{2}{3})=1 \neq -1

B.\\5x-8y=9\ \ \Rightarrow\ \ -8y=-5x+9\ \ \Rightarrow\ \ \ y=  \frac{5}{8}  x-1 \frac{1}{8} \ \Rightarrow\ \ m_1= \frac{5}{8} \\\\12x-5y=7\ \Rightarrow\ \ -5y=-12x+7\ \ \Rightarrow\ \ y= \frac{12}{5}x-1 \frac{2}{5}  \ \ \Rightarrow\ \ m_2= \frac{12}{5} \\\\m_1\cdot m_2= \frac{5}{8} \cdot  \frac{12}{5}= \frac{3}{2}  \neq -1

C.\\y=2x-7\ \ \Rightarrow\ \ m_1=2 \\\\x+2y=3\ \Rightarrow\ \ 2y=-x+3\ \ \Rightarrow\ \ y= -\frac{1}{2}x+1 \frac{1}{2}\ \ \Rightarrow\ \ m_2=- \frac{1}{2} \\\\m_1\cdot m_2= 2 \cdot (- \frac{1}{2})= -1\ \ \Rightarrow\ \ y=2x-7\ \ \ \ \perp\ \ \ \ x+2y=3


D.\\x+6y=8\ \ \Rightarrow\ \ 6y=-x+8\ \ \Rightarrow\ \ \ y=- \frac{1}{6} x+1 \frac{1}{3}\ \ \Rightarrow\ \ m_1= -\frac{1}{6} \\\\y=2x-8\ \Rightarrow\ \ m_2= 2 \\\\m_1\cdot m_2= -\frac{1}{6} \cdot2=- \frac{1}{3} \neq -1
7 0
3 years ago
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