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maks197457 [2]
3 years ago
14

What is the key factor in defining a reaction as an oxidation-reduction reaction?

Chemistry
1 answer:
kari74 [83]3 years ago
6 0

Answer:

Transfer of electrons between atoms

Explanation:

Just because it has the prefix "oxi" it doesn't necessarily mean that oxygen exists as a reactant.

Making and breaking ionic compounds happen right before or after redox reactions after the atoms or ions are modified into one another.

precipitation occurs during the redox rxns involved in electrolysis & daniel cells. but it is not a key factor.

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For the reaction below, the enthalpy change is ΔH = –566 kJ/mol. Increasing the temperature of the system will cause which of th
Lapatulllka [165]

Answer:

The partial pressure of CO₂ will decrease.

Explanation:

The reaction:

2CO (g) + O₂ (g) ⇄ 2CO₂ (g) has a ΔH = –566 kJ/mol. As ΔH<0, the reaction is exothermic.

Le Chatelier's principle says that if a system in chemical equilibrium is subjected to a disturbance it tends to change in a way that opposes this disturbance.

In this case, with increasing of the temperature, the system will produce less heat, doing the equilibrium shifts to the left.

Thus, the partial pressure of both CO and O₂ will increase. And<em> partial pressure of CO₂ will decrease.</em>

I hope it helps!

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3 years ago
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The ______ parts of organisms are most likely to become fossils.
jek_recluse [69]
The hard parts of an organism, such as shells and bones.
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What is hallucination
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<h3>Hallucination is an experience involving the apparent perception of something not present .</h3>

Explanation:

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3 years ago
What is the sum of 16+ -20?
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Determine the pH of a buffer which is a 0.20 M solution of trimethylamine (N(CH3)3) and a 0.40 M solution of trimethylammonium c
uranmaximum [27]

Answer:

pH of the buffer is 10.10

Explanation:

trimethylamine is a weak base that, in presence with its conjugate base, trimethylammonium ion, produce a buffer.

To determine the pH of the buffer we use H-H equation for weak bases:

pOH = pKb + log [Conjugate acid] / [Weak base]

<em>pKb is -log Kb = 4.20</em>

<em />

pOH = 4.20 + log [N(CH₃)₃] / [NH(CH₃)₃]

Replacing the concentrations of the problem:

pOH = 4.20 + log [0.20M] / [0.40M]

pOH = 3.90

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<h3>pH of the buffer is 10.10</h3>

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7 0
4 years ago
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