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Zarrin [17]
3 years ago
14

You could add HCl(aq) to the solution to precipitate out AgCl(s). What volume of a 0.190 M HCl(aq) solution is needed to precipi

tate the silver ions from 12.0 mL of a 0.160 M AgNO3 solution? Express your answer with the appropriate units.
Chemistry
1 answer:
Lemur [1.5K]3 years ago
7 0

Answer: 10.1mL

Explanation:

To solve this problem, let's generate the equation:

HCl + AgNO3 —> AgCl + HNO3

Next, we find the amount of AgNO3 in 12mL of the solution.

12mL = 0.012L

If 0.16mol of AgNO3 dissolves in 1L of solution,

Therefore Xmol will dissolve in 0.012L i.e

Xmol of AgNO3 = 0.16x0.012 = 0.00192mol

From the equation, 1mole of AgNO3 required 1mole HCl.

This implies that 0.00192mol of AgNO3 will also require 0.00192mol of HCl.

From this result, we can calculate the Volume of HCl that is needed for the reaction. This is done by:

Molarity = mole /Volume

Molarity = 0.19M

Mole = 0.00192mol

Volume =?

Volume = mole / Molarity

Volume = 0.00192 / 0.19

Volume = 0.0101L = 10.1mL

Therefore the volume of HCl needed is 10.1mL

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How many particles are present in 12.47 grams of NaCl
liq [111]

Answer:

1.26*10²³ particles are present in 12.47 grams of NaCl

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023 * 10²³ particles per mole. The Avogadro number applies to any substance.

So, first of all you must know the amount of moles that represent 12.47 grams of NaCl. For that it is necessary to know the molar mass.

You know:

  • Na: 23 g/mole
  • Cl: 35.45 g/mole

So the molar mass of NaCl is: 23 g/mole + 35.45 g/mole= 58.45 g/mole

Now you apply a rule of three as follows: if 58.45 grams are present in 1 mole of NaCl, 12.47 grams in how many moles will they be?

moles=\frac{12.47 grams*1 mole}{58.45 grams}

moles= 0.21

You apply a rule of three again, knowing Avogadro's number: if in 1 mole of NaCl there are 6,023 * 10²³ particles, in 0.21 moles how many particles are there?

number of particles=\frac{0.21 moles*6.023*10^{23} }{1 mole}

number of particles= 1.26*10²³

<u><em>1.26*10²³ particles are present in 12.47 grams of NaCl</em></u>

<u><em></em></u>

5 0
3 years ago
Which of the fallowing elements would be least reactive a) iodine b) silicon c) silver d) argon
damaskus [11]

Answer:

Noble Gases

Explanation:It's not on there but Noble gases is the least reactive element because it has 8 electrons and their outer energy is full.

5 0
3 years ago
According to the periodic trends,<br><br> Calcium has a greater atomic radius than magnesium
lions [1.4K]
its radius is smaller
7 0
3 years ago
Read 2 more answers
If 23 atoms of hydrogen are present in the reactants, how many atoms of hydrogen will have to be present in the products?
madam [21]

Answer:

23

Explanation:

law of conservation of mass

quizlet

3 0
2 years ago
What is the difference between a root word and a combining form?
OLEGan [10]

Answer:

The difference is the combining vowel

Explanation:

The Combining form needs the vowel to form, that is:

root word +  combining vowel = combining form

<u>Root word</u>:

A root is a word that does not have a prefix in front of the word or a suffix at the end of the word. The root word is the main lexical unit of a word and a family of words, which carries the most significant aspects of semantic content and cannot be reduced to smaller components

<u>Combining form</u>:

Training process of  words from two or more roots or simple words.

When the word includes a cultured base and a patrimonial base, we will consider derived word. For example, hypermarket, bi-monthly

6 0
3 years ago
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