1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zarrin [17]
3 years ago
14

You could add HCl(aq) to the solution to precipitate out AgCl(s). What volume of a 0.190 M HCl(aq) solution is needed to precipi

tate the silver ions from 12.0 mL of a 0.160 M AgNO3 solution? Express your answer with the appropriate units.
Chemistry
1 answer:
Lemur [1.5K]3 years ago
7 0

Answer: 10.1mL

Explanation:

To solve this problem, let's generate the equation:

HCl + AgNO3 —> AgCl + HNO3

Next, we find the amount of AgNO3 in 12mL of the solution.

12mL = 0.012L

If 0.16mol of AgNO3 dissolves in 1L of solution,

Therefore Xmol will dissolve in 0.012L i.e

Xmol of AgNO3 = 0.16x0.012 = 0.00192mol

From the equation, 1mole of AgNO3 required 1mole HCl.

This implies that 0.00192mol of AgNO3 will also require 0.00192mol of HCl.

From this result, we can calculate the Volume of HCl that is needed for the reaction. This is done by:

Molarity = mole /Volume

Molarity = 0.19M

Mole = 0.00192mol

Volume =?

Volume = mole / Molarity

Volume = 0.00192 / 0.19

Volume = 0.0101L = 10.1mL

Therefore the volume of HCl needed is 10.1mL

You might be interested in
fills a 500.mL flask with 3.6atm of carbon monoxide gas and 1.2atm of water vapor. When the mixture has come to equilibrium she
enot [183]

Answer:

The answer to the question is

The pressure of carbon dioxide after equilibrium is reached the second time is 0.27 atm rounded to 2 significant digits

Explanation:

To solve the question, we note that the mole ratio of the constituent is proportional to their partial pressure

At the first trial the mixture contains

3.6 atm CO

1.2 atm H₂O (g)

Total pressure = 3.6+1.2= 4.8 atm

which gives

3.36 atm CO

0.96 atm H₂O (g)

0.24 atm H₂ (g)

That is

CO+H₂O→CO(g)+H₂ (g)

therefore the mixture contained

0.24 atm CO₂ and the total pressure =

3.36+0.96+0.24+0.24 = 4.8 atm

when an extra 1.8 atm of CO is added we get Increase in the mole fraction of CO we have one mole of CO produces one mole of H₂

At equilibrium we have 0.24*0.24/(3.36*0.96) = 0.017857

adding 1.8 atm CO gives 4.46 atm hence we have

 (0.24+x)(0.24+x)/(4.46-x)(0.96-x) = 0.017857

which gives x = 0.031 atm or x = -0.6183 atm

Dealing with only the positive values we have the pressure of carbon dioxide = 0.24+0.03 = 0.27 atm

7 0
3 years ago
if the Celsius temperature of a gas at constant pressure is increased from 10 Celsius to 20 Celsius the volume is
svet-max [94.6K]

Answer:

               The volume is increased.

Explanation:

                     According to <em>Charles' Law</em>, " <em>at constant pressure the volume and temperature of the gas are directly proportional to each other</em>". Mathematically this law is presented as;

                                                    V₁ / T₁ = V₂ / T₂   -----(1)

In statement the data given is,

T₁  =  10 °C  =  283.15 K                    ∴  K  =  273.15 + °C

T₂  =  20 °C  =  293.15 K

So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,

V₁  =  100 L

V₂  =  Unknown

Now, we will arrange equation 1 for V₂ as,

                                                    V₂  =  V₁ × T₂ / T₁

Putting values,

                                     V₂  = 100 L × 293.15 K / 283.15 K

                                     V₂  = 103.52 L

Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.

3 0
3 years ago
How do you work out question 1a?
Sliva [168]

Answer:

-125 kJ

Explanation:

You calculate the energy required to break all the bonds in the reactants. Then you subtract the energy to break all the bonds in the products.

                     H₂C=CH₂   +    H₂ ⟶    H₃C-CH₃

Bonds:       4C-H + 1C=C     1H-H     6C-H + 1C-C

D/kJ·mol⁻¹:  413       612        436       413      347

The formula relating ΔHrxn and bond dissociation energies (D) is

ΔHrxn = Σ(Dreactants) – Σ(Dproducts)

(Note: This is an exception to the rule. All other thermochemical reactions are “products – reactants”. With bond energies, it’s “reactants – products”. The reason comes from the way we define bond energies.)

<em>For the reactant</em>s:

Σ(Dreactants) = 4 × 413 + 1 × 612 + 1 × 436 = 2700 kJ

<em>For the products:</em>

Σ(Dproducts) = 6 × 413 + 1 × 347 = 2825 kJ

<em>For the system</em> :

ΔHrxn = 2700 - 2825 = -125 kJ

4 0
3 years ago
If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?
Nata [24]

Answer:

The correct answer is option B.

Explanation:

3NaOH+2NBr_3\rightarrow 3HOBr+3NaBr+N_2

Moles of NBr_3 = 40 mol

Moles of NaOH = 48 mol

According to reaction, 3 moles of NaOH reacts with 2 moles NBr_3

Then ,48 moles of NaOH will reacts with:

\frac{2}{3}\times 48 mol=32 mol of NBr_3

Then ,40 moles of NaBr_3 will reacts with:

\frac{3}{2}\times 40 mol=60 mol of NaOH

As we can see that 48 moles of sodium will completey react with 32 moles of nitrogen tribromide.

Moles left after reaction = 40 mol - 32 mol = 8 mol

Hence, the NBr_3 is an excessive reagent.

6 0
3 years ago
Read 2 more answers
If a substance has a mass of 12.50 g and takes up 3.4 mL of space, what is the density?
miskamm [114]

Answer:

The answer is

<h2>3.68 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>density =  \frac{mass}{volume}</h3>

From the question

mass of substance = 12.50 g

volume = 3.4 mL

The density of the substance is

density =  \frac{12.50}{3.4}  \\  = 3.676470588...

We have the final answer as

<h3>3.68 g/mL</h3>

Hope this helps you

7 0
3 years ago
Other questions:
  • A compound, like water, can be broken down (decomposed) by:
    15·2 answers
  • Describe how you would set up an experiment to test the rela-tionship between completion of assigned homework and the fi-nal gra
    6·1 answer
  • What is the minimum number of kilojoules needed to change 40.0 grams of water at 100 degree celsius to steam at the same tempera
    12·1 answer
  • Can someone help me please
    11·1 answer
  • The number of atom of each element present in 2 formula Fe(No3)2​
    15·1 answer
  • If 1.02 g of nickel reacted with 750. mL of 0.112 M hydrobromic acid, how much of each will be present at the end of the reactio
    8·1 answer
  • What is th compound name SO3
    11·1 answer
  • Explain what helps convert non-rich oxygen blood cells back to oxygen rich cells?
    6·1 answer
  • Many homes that are not
    9·1 answer
  • What is a polyprotic buffer?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!