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Zarrin [17]
3 years ago
14

You could add HCl(aq) to the solution to precipitate out AgCl(s). What volume of a 0.190 M HCl(aq) solution is needed to precipi

tate the silver ions from 12.0 mL of a 0.160 M AgNO3 solution? Express your answer with the appropriate units.
Chemistry
1 answer:
Lemur [1.5K]3 years ago
7 0

Answer: 10.1mL

Explanation:

To solve this problem, let's generate the equation:

HCl + AgNO3 —> AgCl + HNO3

Next, we find the amount of AgNO3 in 12mL of the solution.

12mL = 0.012L

If 0.16mol of AgNO3 dissolves in 1L of solution,

Therefore Xmol will dissolve in 0.012L i.e

Xmol of AgNO3 = 0.16x0.012 = 0.00192mol

From the equation, 1mole of AgNO3 required 1mole HCl.

This implies that 0.00192mol of AgNO3 will also require 0.00192mol of HCl.

From this result, we can calculate the Volume of HCl that is needed for the reaction. This is done by:

Molarity = mole /Volume

Molarity = 0.19M

Mole = 0.00192mol

Volume =?

Volume = mole / Molarity

Volume = 0.00192 / 0.19

Volume = 0.0101L = 10.1mL

Therefore the volume of HCl needed is 10.1mL

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Answer:

Explanation:

One of the properties of a liquid is that, <u>it's particles move freely (not tightly packed)</u> hence the reason for <u>it's free flowing (no definite shape)</u> when shaken in a container, unlike a solid whose <u>particles are tightly packed with restricted/no movement</u> and hence the reason for it's compactness and it's definite shape.

When a plastic solid (whose particle is tightly packed and have a restricted movement/no movement) is placed near a heat source, <u>it's particles gains energy in the process and starts to move (though slightly free) and become less tightly packed</u> hence the reason it is observed that plastic solids near a heat source melts.

From the above, it can be deduced that a liquid and a plastic solid near a heat source <u>have there particles move freely (and not tightly packed) hence making the two substances flow freely with no definite shape.</u>

7 0
3 years ago
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The ccorrect answer is C a generator tubrine
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Answer:

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Explanation:

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When you add 10.0 mL of 0.10M KI and 15.0mL, total volume is:

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<em />

And moles of KI are:

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