Answer:
V KOH = 247.939 mL
Explanation:
at the point of equilibrium:
mol CH3COOH = mol KOH.......for weak acid system - strong bases...(1)
⇒ mol CH3COOH = 0.775L * 0.819 mol / L
⇒ mol CH3COOH = 0.634 mol CH3COOH.....(2)
replacing (2) in (1):
0.634 mol = V KOH * 2.56 mol / L
⇒ V KOH = 0.634 mol / (2.56 mol / L )
⇒ V KOH = 0.247939 L ( 247.939 mL )
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