Answer:
Because one calorie is equal to 4.18 J, it takes 4.18 J to raise the temperature of one gram of water by 1°C. In joules, water's specific heat is 4.18 J per gram per °C. If you look at the specific heat graph shown below, you will see that 4.18 is an unusually large value.
A reaction in which energy is absorbed from the surroundings is called anendothermic<span> reaction. In </span>endothermic<span> reactions the enthalpy of the products is greater than the enthalpy of the reactants. Because reactions release or absorb energy, they affect the temperature of their surroundings.
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In most cases, carbon shares electrons with other atoms (usual valence of 4). This is because carbon typically bonds with elements which have a similar electronegativity. Examples of covalent bonds formed by carbon include carbon-carbon, carbon-hydrogen, and carbon-oxygen bonds
1426.58 J and 340.90 calories heat in joules and in calories is required to heat at 28.4g( 1 oz) ice cube from -23C TO 1.0C.
Explanation:
Data given:
mass = 28.4 gram
initial temperature = -23 degrees
final temperature = 1degress
change in temperature ΔT = Tfinal - Tinitial
ΔT = 1 -(-23)
ΔT = 24 degrees
specific heat capacity of ice cube c = 2.093 J/g C
Formula used:
q = mc ΔT
putting the values in the equation:
q= 28.4 x 2.093 x 24
= 1426.58 J
ENERGY IN CALORIES:
340.90 calories is the energy is required in the process.
