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lubasha [3.4K]
4 years ago
5

HelpUsing a 2-cm-thick piece of cardboard over a radiation source would be mosteffective for protecting against which type of ra

diation?O A) betaO B) X-rayO C) alphaO D) gamma

Chemistry
2 answers:
Studentka2010 [4]4 years ago
4 0

Answer:

I believe the answer is C) Alpha radiation.

Lisa [10]4 years ago
3 0
It would protect best against C) Alpha radiation, as Beta radiation is stopped by lighter metals such as aluminium, and Gamma radiation can only be stopped by heavier metals such as lead.
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Magnesium nitrate contains chemical bonds that are
SVETLANKA909090 [29]

Answer:

Magnesium Nitrate is an ionic compound formed by:

Magnesium;Mg+2 (<em>the cation)</em> and Nitrate NO−3 (<em>the poly-atomic anion)</em>.

In order for these two ions to bond, the charges must be equal and opposite. Therefore, it will take:

     <u>two -1 nitrate ions</u> <u>to balance the</u> <u>one +2 magnesium ion</u>.

3 0
2 years ago
How many formula units make up 16.4 g of magnesium chloride (MgCl2)?
Svetach [21]

<span>molar mass of MgCl2  = 24.32 + 2 x (35.45) = 95.22 g</span><span>

<span>16.4g MgCl2 x (1 mol MgCl2/95.22 g MgCl2) = 0.172 mol MgCl2 </span>
 </span>
<span>0.172 mol MgCl2 x (6.022 x 10^23/1 mol MgCl2) = 10.36 x 10^22 atoms<span> </span></span>

8 0
3 years ago
Read 2 more answers
What statements are always true about limiting reactants?
alisha [4.7K]

Answer:

5.The limiting reactant is completely used up in the reaction

Explanation:

The limiting reactant is completely used up in the reaction is the correct answer because a limiting reactant is a reactant in chemical reaction that is completely consumed or used up in the chemical reaction. Limiting reactant when it is completely used up limits the amount of products that will be formed. The reaction will be halted or will stop when the limiting reactant is totally used up.

7 0
3 years ago
When we looked at assigning the electrons in nitrogen to sites in the 2s and 2p orbitals, we used the 2s anti-bonding site. Whic
AveGali [126]

Answer:

B) Although this site is not desirable for making a bond between atoms, it is a good site in the sense that the electrons can be close to the nucleus.  

Explanation:

An antibonding orbital points away from the nuclei, with a node between them, so the electrons are not held close to the nuclei. The orbital is not desirable for bonding.

The diagram below shows a σ*1s molecular orbital, but a σ*2s orbital has a similar shape.

A) is true. The σ*1s orbital has the lowest energy.

C) is true. Any orbital can accommodate at most one electron pair.

D) is may be true. Orbital energy decreases as atomic number increases, so the orbital energy of an N₂ σ*2s molecule may be close to that of a sulfur atom's 2s orbital.

6 0
4 years ago
A 8.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
Ne4ueva [31]

Answer:

C3H6.

Explanation:

Data obtained from the question:

Mass of the compound = 8g

Mass of CO2 = 24.01g

Mass of H2O = 13.10g

Next, we shall determine the mass of C, H and O present in the compound. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of C in compound = Mass of C/Molar Mass of CO2 x 24.01

=> 12/44 x 24.01 = 6.5g

Mass of H in the compound = Mass of H/Molar Mass of H2O x 13.1

=> 2x1/18 x 13.1 = 1.5g

Mass of O in the compound = Mass of compound – (mass of C + Mass of H)

=> 8 – (6.5 + 1.5) = 0

Next, we shall determine the empirical formula of the compound. This is illustrated below:

C = 6.5g

H = 1.

Divide by their molar mass

C = 6.5/12 = 0.54

H = 1.4/1 = 1.

Divide by the smallest

C = 0.54/0.54 = 1

H = 1/0.54 = 2

Therefore, the empirical formula is CH2

Finally, we shall determine the molecular formula as follow:

The molecular formula of a compound is a multiple of the empirical formula.

Molecular formula = [CH2]n

[CH2]n = 44

[12 + (2x1)]n = 44

14n = 44

Divide both side by 14

n = 44/14

n = 3

Molecular formula = [CH2]n = [CH2]3 = C3H6

Therefore, the molecular formula of the compound is C3H6

4 0
3 years ago
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