The question is incomplete, the complete question is;
Using the following equation 2 NaOH(aq) + H2SO4(aq) → 2 H2O(aq) + Na2SO4(aq) how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid
Answer:
355.1 g
Explanation:
The equation of the reaction is;
2 NaOH(aq) + H2SO4(aq) → 2 H2O(aq) + Na2SO4(aq)
We have been told that H2SO4 is in excess so NaOH is the limiting reactant. Therefore;
Number of moles in 200g of NaOH = 200g/40g/mol = 5 moles
So;
2 moles of NaOH yields 1 mole of Na2SO4
5 moles of NaOH will yield 5 * 1/2 = 2.5 moles of Na2SO4
Molar mass of Na2SO4 = 142.04 g/mol
Mass of Na2SO4= 2.5 moles * 142.04 g/mol = 355.1 g
The molecule C3H6 is classified as a Alkene.
Answer:
friction
Explanation:
The rubbing of certain materials against one another can transfer negative charges, or electrons.
Answer:
Percent yield = 86.2%
Explanation:
Given data:
Mass of zinc = 3.68 g
Mass of zinc chloride = ?
Percent yield = ?
Actual yield = 7.12 g
Solution:
Chemical equation:
Zn + 2HCl → ZnCl₂ + H₂
Number of moles of zinc:
Number of moles = Mass /molar mass
Number of moles = 3.68 g / 65.38 g/mol
Number of moles = 0.06 mol
Now we will compare the moles of ZnCl₂ with zinc.
Zn : ZnCl₂
1 : 1
0.06 : 0.06
Theoretical yield of zinc chloride:
Mass of ZnCl₂ = moles × molar mass
Mass of ZnCl₂ = 0.06 mol × 136.286 g/mol
Mass of ZnCl₂ = 8.2 g
Percent yield:
Percent yield = actual yield / theoretical yield × 100
Percent yield = 7.12 g/ 8.2 g × 100
Percent yield = 86.2%
The differential change in entropy of a system is
given as: <span>
<span>dS = (∂S/∂T)_V dT </span>
We also know that </span>
<span>(∂S/∂T)_V = n*Cv/T, </span>
Where Cv is the molar heat capacity at constant
volume, and n is the number of moles. Combining the 2 equations:<span>
dS = n*Cv/T dT
Since Cv is constant as stated in the problem, therefore we
integrate the differential equation. Leading us to:
ΔS = n*Cv*ln(Tfinal/Tinitial)
<span>We are given that: V =
18L volume at P=2 kPa and T=298.15K. </span></span>
Using the ideal gas law to find the number of
moles of gas: <span>
n = p*V/R*T = (2kPa)*(18L)/((298.15K)*(8.314 L*kPa/(mol*K)))
n = 1.45*10^-2 mol
Going back to the entropy change:
ΔS = (1.45*10^-2 mol)*(20.17 J/(K*mol))*ln(1073.15/298.15)
<span>
<span>ΔS = 0.375 J/K</span></span></span>
