The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is 6.18 * 10⁴ Kg of ammonia.
<h3>What mass in kilograms of ammonia are required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄?</h3>
The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is determined from the mole ratio of the reaction.
The mole ratio of the reaction is obtained from the balanced equation of the reaction given below:
- 2NH₃(g) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)
Mole ratio of NH₃ and (NH₄)₂SO₄ is 2: 1
Mass of 2 moles of ammonia = 2 * 17 = 34 g
Mass of 1 mole of (NH₄)₂SO₄ = 132 g
Mass of ammonia required = 34/132 * 2.40 × 10⁵ kg
Mass of ammonia required = 6.18 * 10⁴ Kg of ammonia.
In conclusion, the mole ratio is used to determine the mass of ammonia required.
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Answer:
It becomes shorter
Explanation:
A wave, such as a Soundwave, controls volume based on it's Wavelength. A Louder sound has a shorter wavelength, a softer sound has it's waves spread out more. Amplitude is simply a fancy name for Volume in Amps. When amplitude increases, the volume increases. Thus, waves become shorter.
Answer:
This looks like a hard question for me is this biology
Explanation:
Answer:
The statement is FALSE.
Explanation:
It is known as the ion effect common to the displacement of an ionic equilibrium when the concentration of one of the ions that are involved in said equilibrium changes, due to the presence in the dissolution of a salt that is dissolved in it.
Given the reaction of the dissociation reaction of a weak electrolyte:
AB (s) ⇔ A⁺(aq) + B⁻ (aq)
The equilibrium constant of the reaction is:
![K_{ps}=\frac{[A^+][B^-]}{[AB]}](https://tex.z-dn.net/?f=K_%7Bps%7D%3D%5Cfrac%7B%5BA%5E%2B%5D%5BB%5E-%5D%7D%7B%5BAB%5D%7D)
Given the reaction of the dissociation reaction of a stong electrolyte:
CB (s) ⇒ C⁺(aq) + B⁻ (aq)
If the electrolyte CB is added to the medium in which electrolyte AB is found, the medium will have a common ion B⁻:
AB (s) ⇔ A⁺(aq) + B⁻ (aq)
CB (s) ⇒ C⁺(aq) + B⁻ (aq)
By the Le Chatelier's principle, having more concentration of products, the balance will shift to the right.
Hence, the extent of ionization of a weak electrolyte is decreased by adding to the solution a strong electrolyte that has an ion in common with the weak electrolyte.