Answer:
a0=2
a1=3
a2=2
a3=4
Explanation:
The balanced equation for the complete combustion of methane is:
2CH₃OH₍l₎ + 3O₂₍g₎ → 2CO₂ + 4H₂O₍l₎
This way, there is an equal number of atoms of each kind on both reactants side and the products side.
Therefore the coefficients represented by the unknowns are:
a0=2
a1=3
a2=2
a3=4
The above is the equation for the complete combustion of methanol.
Answer is: <span>c. 80 g of Br2.
</span>1) n(Li) = 14 g ÷ 7 g/mol
n(Li) = 2 mol.
N(Li) = 2 mol · 6·10²³ 1/mol.
N(Li) = 1,2·10²⁴.
2) n(He) = 4 g ÷ 4 g/mol.
n(He) = 1 mol.
N(He) = 1 mol · 6·10²³ 1/mol.
N(He) = 6·10²³.
3) n(Br₂) = 80 g ÷ 160 g/mol.
n(Br₂) = 0,5 mol.
N(Br₂) = 0,5 mol · 6·10²³ 1/mol.
N(Br₂) = 3·10²³.
4) n(H₂) = 4 g ÷ 2 g/mol = 2 mol.
N(H₂) = 1,2·10²⁴.
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The answer would be Propane. The formula for Propane is C3H8
Answer: 154.09 g
Explanation:
3 Mg + 2 FeCl3 = 3 MgCl2 + 2 Fe
The mass of MgCl2 produced is calculated:
m MgCl2 = 175 g FeCl3 * (1 mol FeCl3 / 162.2 g) * (3 mol MgCl2 / 2 mol FeCl3) * (95.21 g MgCl2 / 1 mol) = 154.09 g