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Ivanshal [37]
2 years ago
13

What is the value of angle X and angle Y in the triangle diagram below?

Mathematics
1 answer:
andre [41]2 years ago
3 0

Sum of two interior angles=exterior angle

\\ \rm\Rrightarrow 45+65=y

\\ \rm\Rrightarrow y=110

  • Linear pairs have sum 180

\\ \rm\Rrightarrow x+y=180

\\ \rm\Rrightarrow x+110=180

\\ \rm\Rrightarrow x=70

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Find the slope of the line
olga55 [171]

Answer:

slope or m = -1

Step-by-step explanation:

The slope formula is:

y2-y1         -3 - 1             -4          -4

-------- =   -------------- = --------- =  ----- = -1

x2-x1       1  - (-3)            1+3         4

So, the slope is -1 XD YAY!!

6 0
3 years ago
Read 2 more answers
Using sum or difference formulas, find the exact value of sin(165∘)
Nikitich [7]
\bf \textit{Sum and Difference Identities}
\\ \quad \\
sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\ \quad \\
sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})\\\\
-------------------------------\\\\

\bf sin(165^o)\implies sin(120^o+45^o)
\\\\\\
sin(120^o)cos(45^o)~+~cos(120^o)sin(45^o)\implies \cfrac{\sqrt{3}}{2}\cdot \cfrac{\sqrt{2}}{2}~+~\cfrac{-1}{2}\cdot \cfrac{\sqrt{2}}{2}
\\\\\\
\cfrac{\sqrt{6}}{4}~-~\cfrac{\sqrt{2}}{4}\implies \cfrac{\sqrt{6}-\sqrt{2}}{4}
6 0
3 years ago
The perimeter of a rectangle is 300 feet. The width of the rectangle is 10 feet more than the length. What is the width of the r
gavmur [86]
300 = 2(x + x + 10)
300 = 2(2x +10)
300 = 4x + 20
4x = 280
x = 70
x + 10 = 80
width = 80ft
answer <span>D) 80 feet</span>
7 0
3 years ago
2^8+6(7-1)+4 does this equal 56
sukhopar [10]

Answer:

nope

Step-by-step explanation:

it acutally equals to 292 I am sure!

7 0
3 years ago
You open a drink stand where you sell coffee and hot chocolate. You sell coffee for $1.80 and hot chocolate for $3.15. At the en
Usimov [2.4K]

Answer:

c = 69 and h = 51

Step-by-step explanation:

You will need two different equations here

use variable c as coffee and variable h as hot chocolate

c + h = 120

1.80c + 3.15h = 284.40

By moving variables, you can alter the first equation

h = 120 - c

Now insert this into the second equation

1.80c + 3.15(120 - c) = 284.40

Multiply

1.80c + 378 - 3.15c = 284.40

Subtract the c

-1.35c + 378 = 284.40

Subtract 378 from both sides

-1.35c = -93.6

Divide both sides by -1.35

c = 69

Then plug into the first equation

69 + h = 120

Subtract 69

h = 51

7 0
3 years ago
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