Answer:
1) C
2) B
3) D
4) B
5) C
6) B
7) F
8) B
9) B
10) B
11) D
Step-by-step explanation:
1) The restaurants were measured for each restaurant to give ratings as observations is being carried out on restaurants
2) The percentage of customers was measured to determine ratings. The food and decor can't be measured. Seating capacity is not a measurement variable.
3) The date of measurement is not mentioned
4) The measurement would have to be taken at restaurant obviously.
5) The measurments were taken to determine the ratings and decide the best restaurant
6) Since percentage of customers was measured, the customers had to be surveyed.
7) There are no categorical variables. All variables were measured on the scale of 30
8) Quantitative variable under investigation is number of customers who returned.
9) This is a survey not a design experiment. In design experiment, somethig is put on a test.
10) This is a cross-sectional data. nothing is being measurd over a period of time
11) There are no specific ocncerns since no data is mentioned in the question.
Answer:
The answer is: One loaf of bread contains one and halve cups of flour.
Answer:he must save an average of $150 or more in each of the remaining 8 months.
Step-by-step explanation:
Mr. Helsley wishes to save at least $1500 in 12 months. If he saved $300 during the first 4 months, then the amount left would be
≥ 1500 - 300
Let x represent the least possible average amount that he must save in each of the remaining 8 months. This means that the total amount that he would save in the last 8 months would be 8x. Therefore,
300 + 8x ≥ 1500
8x ≥ 1500 - 300
8x ≥ 1200
x ≥1200/8
x ≥ 150
Answer:
∫▒〖arctan(x).1 dx=arctan(x).x〗-1/2 ln(1+x^2 )+C
Step-by-step explanation:
∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗
Let 1st=arctan(x)
And 2nd=1
∫▒〖arctan(x).1 dx=arctan(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗
As we know that
derivative of arctan(x)=1/(1+x^2 )
∫▒〖1 dx〗=x
So
∫▒〖arctan(x).1 dx=arctan(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1
Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now
Let 1+x^2=u
du=2xdx
Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get
1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)
1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)
1/2 ∫▒(2xdx/u) =1/2 ln(u)+C
1/2 ∫▒(2xdx/u) =1/2 ln(1+x^2 )+C
Putting values in Eq1 we get
∫▒〖arctan(x).1 dx=arctan(x).x〗-1/2 ln(1+x^2 )+C (required soultion)
Answer:
11/3 divides by 60/11 = 660/33 = 20
Step-by-step explanation: