Depends on what you're trying to study
-4x + 6y = 12
x + 2y = -10
First solve for x in the second equation
x + 2y = -10
x = -10 - 2y
Now we have a value for x so we can substitute it into the other equation
-4 (-10 - 2y) + 6y = 12
Now solve for y
40 + 8y + 6y = 12
40 + 14y = 12
14y = -28
y = -2
Now we have a value for y that we can plug into one of the original equations so we can solve for x
x + 2y = -10
x + 2(-2) = -10
x - 4 = -10
x = -6
Your solution set is
(-6, -2)
Answer:
I'm pretty sure it's 24.516
Given:
Diagram of a circle and its two secant from an exterior point.
To find:
The value of x.
Solution:
We know that, If two secant are on a circle from an exterior point, then the products of measure of secants and measure of external segments of secants are equal.
Using the above property, we get
Splitting the middle term, we get
Using zero product property, we get
and 
and 
Side cannot be negative.
Therefore, the only possible value of x is 1.
Answer:
-70x, 26y^3, -3z
Step-by-step explanation:
The way to solve this is by combining like terms. The terms we have given to us include x, y^3, and z. As a result, we will group terms based on these variables.
1. Find all the terms with each variable.
* -35x, -35x
* 23y^3, 3y^3
* -3z
2. Combine like terms.
* -35x + (-35x) = -35x - 35x = -70x
* 23y^3 + 3y^3 = 26y^3
* -3z + 0 = -3z
