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2 years ago

Sunday bought a piece of fabric that is 500 cm long.What is this length in meters?

Mathematics

2 answers:

viva [34]2 years ago

6 0

Answer:

5 m

Step-by-step explanation:

1 m = 100cm

therefore

5m = 500 cm

REY [17]2 years ago

4 0

Answer:

5 meters.

Step-by-step explanation:

To find the difference between meter and centimeter, base it on the power of digit-to-decimal or digit-to-hundreds place. Simplified, to find a meter and centimeter difference, divide the centimeter by 100.

Example number: <em>Let's say </em>35 is your centimeters. Your meters would be 0.35.

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Earth has a mass of 5.97 × 1024 kg and Venus has a mass of 4.87 × 1024 kg. How much more mass does Earth have than Venus? Earth

dezoksy [38]

Answer:

The answer to your question is a = 1.1; b = 24

Step-by-step explanation:

Data

Earth's mass = 5.97 x 10²⁴ kg

Venus' mass = 4.87 x 10²⁴ kg

Process

1.- Subtract the Venus' mass to the earth's mass.

5.97

1.1

2.- Write the result in scientific notation

1.1 x 10²⁴ kg

3.- Result

a = 1.1

b = 24

7 0

2 years ago

1) Qual é a equação que representa o perímetro de 103 cm de um triângulo escaleno? *

4vir4ik [10]

C c c c c c c c gc c c. C ccc

6 0

2 years ago

Write the number 0.72 repeating as a fraction or mixed number.

34kurt

8/11 is the fraction

To derive this simply put

72.727272/100 and it reduces to 8/11

8 0

2 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

Someone help. You do not have to explain it

nadezda [96]

Answer:

x=0, y=3

x=5, y= 2

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers