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2 years ago

CAN U PLEASE DRAW ON IT LIKE SAVE IT AND DRAW ON IT PLEASE

Mathematics

1 answer:

fiasKO [112]2 years ago

5 0

Answer:

Umm here BUT DONT JUDGE I HAD TO DO THIS ON MICROSOFT PAINT WITH A MOUSE AND IT WAS NOT FUN slope= 3/4

Step-by-step explanation:

ok if this is wrong sry :C

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What is -7 (3a-1)=91 what does a equal

Nastasia [14]

Answer:

a = -4

Step-by-step explanation:

Solve for a:

-7 (3 a - 1) = 91

Divide both sides of -7 (3 a - 1) = 91 by -7:

(-7 (3 a - 1))/(-7) = 91/(-7)

(-7)/(-7) = 1:

3 a - 1 = 91/(-7)

The gcd of 91 and -7 is 7, so 91/(-7) = (7×13)/(7 (-1)) = 7/7×13/(-1) = 13/(-1):

3 a - 1 = 13/(-1)

Multiply numerator and denominator of 13/(-1) by -1:

3 a - 1 = -13

Add 1 to both sides:

3 a + (1 - 1) = 1 - 13

1 - 1 = 0:

3 a = 1 - 13

1 - 13 = -12:

3 a = -12

Divide both sides of 3 a = -12 by 3:

(3 a)/3 = (-12)/3

3/3 = 1:

a = (-12)/3

The gcd of -12 and 3 is 3, so (-12)/3 = (3 (-4))/(3×1) = 3/3×-4 = -4:

Answer: a = -4

6 0

4 years ago

Read 2 more answers

Write an equation in point slope form that passes through (3,-1) and has a slope of 2?

dusya [7]

Answer:

y+1 = 2 (x -3)

Step-by-step explanation:

The formula for point slope form is --

Y - Y1 = m ( x - x1)

M being slope, y1 and x1 being the values.

since the y value is negative, double negative is positive so instead of minus 1 it would be plus 1

7 0

3 years ago

Suppose a ball is dropped from a height of 16 feet. Each time it drops h feet, it rebounds 0.81h feet. Find the total distance t

Roman55 [17]

When the ball is first dropped, it falls $h$ feet. On the first bounce, it rebounds $0.81h$ feet, which means on the second "drop" it must travel $0.81h$ feet again. On the second bounce, the ball rebounds $0.81(0.81h)=0.81^2h$ feet, and on the third drop falls the same distance. And so on.

So there are two directions to track:

$\text{downward: }\displaystyle h+0.81h+0.81^2h+\cdots=\sum_{n=0}^\infty 0.81^nh$
$\text{upward: }\displaystyle 0.81h+0.81^2h+\cdots=\sum_{n=1}^\infty 0.81^nh$

The total distance is the sum of these two:

$\displaystyle\sum_{n=0}^\infty 0.81^nh+\sum_{n=1}^\infty 0.81^nh=h+2h\sum_{n=1}^\infty 0.81^n$

Recall that for an infinite geometric sum, you have

$\displaystyle\sum_{n=0}^\infty r^n=1+\sum_{n=1}^\infty r^n=\frac1{1-r}$

provided that $|r|$ . So the total distance traveled by the ball is

$h+2h\left(\dfrac1{1-0.81}-1\right)\approx9.53h$

Starting with a height of $h=16$ means the total distance is about 152.42 ft.