9514 1404 393
Answer:
C = 9x +2280
Step-by-step explanation:
The 2-point form of the equation for a line can be a place to start.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
C = (4800 -3000)/(280 -80)(x -80) +3000 . . . . . use given values
C = 1800/200(x -80) +3000 . . . . simplify some
C = 9x -720 +3000 . . . . eliminate parentheses
C = 9x +2280
Answer:
B
Step-by-step explanation:
Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Answer:
B
Step-by-step explanation:
You would get the verification notice from the school of your enrollment I belive.